Problem 42 IR Spectrum (liquid film) 1768 1746 1190 4000 3000 2000 1600 1200 800 v (cm") 100- Mass Spectrum 29 80 60 20 M**= 146 (<1%) C6H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH21 CH, t CH solvent proton decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (200 MHz, CDCI, solution) TMS 9 8 7 6 5 4 3 1 8 (ppm) 10 131 % of base peak 21

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Problem 42
IR Spectrum
(liquid film)
1768
W 1746
1190
2000
21
4000
3000
1600
1200
800
v (cm'
100F
80
60
Mass Spectrum
29
40
20
M*'= 146 (<1%)
C3H10 04
40
80
120
160
200
240
280
m/e
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
DEPT CH CH, сн
solvent
proton decoupled
200
160
120
80
40
0 8 (ppm)
1H NMR Spectrum
(200 MHz, CDCI, solution)
TMS
10
9
8
7
6
4
2
1
8 (ppm)
131
% of base peak
Transcribed Image Text:Problem 42 IR Spectrum (liquid film) 1768 W 1746 1190 2000 21 4000 3000 1600 1200 800 v (cm' 100F 80 60 Mass Spectrum 29 40 20 M*'= 146 (<1%) C3H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH CH, сн solvent proton decoupled 200 160 120 80 40 0 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) TMS 10 9 8 7 6 4 2 1 8 (ppm) 131 % of base peak
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