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Problem 4.27 (Node-Voltage Method) Find the branch currents i1, iz, and is 1 ΚΩ 30 V + 5 kΩ V. π 10 mA 500 Ω Va ξεκαθα ig + 54 kΩ ; 80 V

Problem 4.27 (Node-Voltage Method) Find the branch currents i1, iz, and is 1 ΚΩ 30 V + 5 kΩ V. π 10 mA 500 Ω Va ξεκαθα ig + 54 kΩ ; 80 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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4.27
**Problem 4.27 (Node-Voltage Method)** Find the branch currents \(i_1\), \(i_2\), and \(i_3\). **Circuit Diagram Description:** 1. The circuit consists of a voltage source of 30V connected in series with a 5 kΩ resistor and a current source of 10 mA. 2. The node between the 5 kΩ resistor and the current source is labeled as \(V_1\). 3. The current source is connected in parallel to another resistor of 500 Ω, with the node across the resistor labeled as \(V_2\). 4. Parallel to the 500 Ω resistor is a 1 kΩ resistor, positioned horizontally, connecting back to the junction between the 5 kΩ resistor and the 10 mA current source. 5. From the node labeled \(V_2\), another branch goes through a 4 kΩ resistor to an 80V voltage source, completing the circuit loop. 6. The branch currents are labeled as \(i_1\) through the 5 kΩ resistor, \(i_2\) through the 500 Ω resistor, and \(i_3\) through the 4 kΩ resistor. The goal is to determine the values of these branch currents using the node-voltage method.
Transcribed Image Text:**Problem 4.27 (Node-Voltage Method)** Find the branch currents \(i_1\), \(i_2\), and \(i_3\). **Circuit Diagram Description:** 1. The circuit consists of a voltage source of 30V connected in series with a 5 kΩ resistor and a current source of 10 mA. 2. The node between the 5 kΩ resistor and the current source is labeled as \(V_1\). 3. The current source is connected in parallel to another resistor of 500 Ω, with the node across the resistor labeled as \(V_2\). 4. Parallel to the 500 Ω resistor is a 1 kΩ resistor, positioned horizontally, connecting back to the junction between the 5 kΩ resistor and the 10 mA current source. 5. From the node labeled \(V_2\), another branch goes through a 4 kΩ resistor to an 80V voltage source, completing the circuit loop. 6. The branch currents are labeled as \(i_1\) through the 5 kΩ resistor, \(i_2\) through the 500 Ω resistor, and \(i_3\) through the 4 kΩ resistor. The goal is to determine the values of these branch currents using the node-voltage method.
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