Problem 4.01. A carnot refrigerator (carnot cycle heat pump in reverse) operating between Th and Te is used to cool and freeze a bottle of water, volume V, at a temperature To < Th to freezing temperature T (known density Pw, heat capacity cw). (a) Find the work required to cool and freeze the water. (b) Find the change in entropy in the heat baths, and use it to place a limit on the change in entropy of the water (without calculating the entropy change in the water). The C.O.P. of a carnot refrigerator: KR= Qc W Th Te = - Te
Problem 4.01. A carnot refrigerator (carnot cycle heat pump in reverse) operating between Th and Te is used to cool and freeze a bottle of water, volume V, at a temperature To < Th to freezing temperature T (known density Pw, heat capacity cw). (a) Find the work required to cool and freeze the water. (b) Find the change in entropy in the heat baths, and use it to place a limit on the change in entropy of the water (without calculating the entropy change in the water). The C.O.P. of a carnot refrigerator: KR= Qc W Th Te = - Te
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:Problem 4.01. A carnot refrigerator (carnot cycle heat pump in reverse) operating between Th and Te is
used to cool and freeze a bottle of water, volume V, at a temperature To < Th to freezing temperature T
(known density Pw, heat capacity cw). (a) Find the work required to cool and freeze the water. (b) Find
the change in entropy in the heat baths, and use it to place a limit on the change in entropy of the water
(without calculating the entropy change in the water).
The C.O.P. of a carnot refrigerator:
KR=
Qc
=
W
Te
Th-Te
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