Problem 4. (9-10) The side girder shown in the photo supports the boat and deck. An idealized model of this girder is shown in the figure, where it can be assumed A is a roller and B is a pin. Using a locale code, the anticipated deck loading transmitted to the girder is 6 kN/m. Wind exerts a resultant horizontal force of 4 kN as shown, and the mass of the boat that is supported by the girder is 23 Mg. The boat's mass center is at G. Determine the reactions at the supports.

Problem 4. (9-10) The side girder shown in the photo supports the boat and deck. An idealized model of this girder is shown in the figure, where it can be assumed A is a roller and B is a pin. Using a locale code, the anticipated deck loading transmitted to the girder is 6 kN/m. Wind exerts a resultant horizontal force of 4 kN as shown, and the mass of the boat that is supported by the girder is 23 Mg. The boat's mass center is at G. Determine the reactions at the supports.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.7.9P

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Concept explainers

Steel Framing

A steel frame consists of a skeleton frame structure comprising of horizontal I-beams and vertical steel columns fitted in a rectangular grid building construction to brace the floors, walls, and the roof of the building held onto the frame. Due to the implementation of this methodology, the construction of the skyscrapers was feasible.

Question

Problem 4. (9-10) The side girder shown in
the photo supports the boạt and deck. An
idealized model of this girder is shown in the
figure, where it can be assumed A is a roller
and B is a pin. Using a locale code, the
anticipated deck loading transmitted to the
girder is 6 kN/m. Wind exerts a resultant
horizontal force of 4 kN as shown, and the
mass of the boat that is supported by the
girder is 23 Mg. The boat's mass center is at
G. Determine the reactions at the supports.
F1.60 m--1.80 m-
-2 m-
6 kN/m
4 kN
0.30 m
(a)
6 (3.80) = 22.8 kN
4 kN
0.30jm
B,
B
-3.40m-
-1.90m
10.10 m
A,
23 (9.81) kN = 225.6 kN
(b)

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