Problem 4: Water flows through a water hose at a rate of Q1 = 660 cm/s, the diameter of the hose is d = 2.13 cm. A nozzle is attached to the waterhose. The water leaves the nozzle at a velocity of v = 11.6 m/s.Part (a) Enter an expression for the cross-sectional area of the hose, A1, in terms of its diameter, dj.A1 =789HOMEA1d45digh12.3PQ1ENDmtV1V2vol BACKSPACE DEL CLEARSubmitHintFeedbackI give up!Part (b) Calculate the numerical value of A1, in square centimeters.Part (c) Enter an expression for the speed of the water in the hose, v1, in terms of the volume flow rate O, and cross-sectional area A1.Part (d) Calculate the speed of the water in the hose, vị in meters per second.Part (e) Enter an expression for the cross-sectional area of the nozzle, A2, in terms of vị, v2 and A1.Part (f) Calculate the cross-sectional area of the nozzle, A2 in square centimeters.

Solution:-Given thatQ1=660 cm3/sd1=2.13 cmV2=11.6 m/s

Answered: Problem 4: Water flows through a water…

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