Problem 4: The Slingshot is a ride for two people. It consists of a single passenger cage, two towers, and two elastic bands. Potential energy is stored in the elastic bands and the passenger cage is released. On the way up, this potential energy in the elastic bands is converted into the kinetic energy of the cage. At the maximum height of the ride, the energy has been converted into gravitational potential energy of the cage. The slingshot has two towers of height h = 73 m. The towers are a distance d = 31 m apart. Each elastic band has an unstretched length of Lo = 41 m and a spring constant of k = 295 N/m. The total mass of the passengers and cage is m = 410 kg. The car is pulled down to the ground in the middle of the two towers. MI h, Otheexpertta.com Part (a) Write an expression for the stretched length L of one of the elastic bands strung from the cage to the top of its tower. MultipleChoice : 1) h² + d² 2) (h² + d² )!/2 3) (h² + d² )!/2 - Lo 4) (h? + (d/2)2 )/2 - Lo 5) h² + (d/2)² 6) (h? + (d/2)2 )/2 Part (b) Calculate the stretched length, in meters, of each band. Numeric : A numeric value is expected and not an expression. L = Part (c) Write an expression for the total potential energy stored in the elastic bands before the cage is released. MultipleChoice : 1) k ( h? + (d/2)²)2 2) k ( h2 + (d/2)² ) 3) k/2 ( h² + (d/2)² ) 4) k/2 ( ( h² + (d/2)² )2 - Lo )² 5) k ( h? + (d/2)2 - Lo )² 6) k ( (h² + (d/2)² )/2 - Lo )² Part (d) Calculate the total potential energy, in joules, stored in the elastic bands before the cage is released. Numeric : Anumeric value is expected and not an expression. U = Part (e) Calculate the maximum height, in meters, of the ride. Numeric : A numeric value is expected and not an expression. hf=
Problem 4: The Slingshot is a ride for two people. It consists of a single passenger cage, two towers, and two elastic bands. Potential energy is stored in the elastic bands and the passenger cage is released. On the way up, this potential energy in the elastic bands is converted into the kinetic energy of the cage. At the maximum height of the ride, the energy has been converted into gravitational potential energy of the cage. The slingshot has two towers of height h = 73 m. The towers are a distance d = 31 m apart. Each elastic band has an unstretched length of Lo = 41 m and a spring constant of k = 295 N/m. The total mass of the passengers and cage is m = 410 kg. The car is pulled down to the ground in the middle of the two towers. MI h, Otheexpertta.com Part (a) Write an expression for the stretched length L of one of the elastic bands strung from the cage to the top of its tower. MultipleChoice : 1) h² + d² 2) (h² + d² )!/2 3) (h² + d² )!/2 - Lo 4) (h? + (d/2)2 )/2 - Lo 5) h² + (d/2)² 6) (h? + (d/2)2 )/2 Part (b) Calculate the stretched length, in meters, of each band. Numeric : A numeric value is expected and not an expression. L = Part (c) Write an expression for the total potential energy stored in the elastic bands before the cage is released. MultipleChoice : 1) k ( h? + (d/2)²)2 2) k ( h2 + (d/2)² ) 3) k/2 ( h² + (d/2)² ) 4) k/2 ( ( h² + (d/2)² )2 - Lo )² 5) k ( h? + (d/2)2 - Lo )² 6) k ( (h² + (d/2)² )/2 - Lo )² Part (d) Calculate the total potential energy, in joules, stored in the elastic bands before the cage is released. Numeric : Anumeric value is expected and not an expression. U = Part (e) Calculate the maximum height, in meters, of the ride. Numeric : A numeric value is expected and not an expression. hf=
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Conservation and Energy Q4: please answer all parts and explain reasoning (even if minor). Part a is answered.
Transcribed Image Text:Problem 4: The Slingshot is a ride for two people. It consists of a single passenger
cage, two towers, and two elastic bands. Potential energy is stored in the elastic bands
and the passenger cage is released. On the way up, this potential energy in the elastic
bands is converted into the kinetic energy of the cage. At the maximum height of the
ride, the energy has been converted into gravitational potential energy of the cage. The
slingshot has two towers of height h = 73 m. The towers are a distance d = 31 m apart.
Each elastic band has an unstretched length of Lo = 41 m and a spring constant of k =
MI
295 N/m. The total mass of the passengers and cage is m = 410 kg. The car is pulled
down to the ground in the middle of the two towers.
©theexpertta.com
Part (a) Write an expression for the stretched length L of one of the elastic bands strung from the cage to the top of its tower.
MultipleChoice :
|1) h² + d²
2) ( h² + d² )!/2
3) ( h² + d² )!/2 - Lo
4) (h² + (d/2)² )1/2 - Lo
5) h? + (d/2)?
6) (h² + (d/2)² )\/2
Part (b) Calculate the stretched length, in meters, of each band.
Numeric : A numeric value is expected and not an expression.
L =
Part (c) Write an expression for the total potential energy stored in the elastic bands before the cage is released.
MultipleChoice:
1) k ( h² + (d/2)²)²
2) k ( h² + (d/2)² )
3) k/2 ( h² + (d/2)² )
4) k/2 ( ( h² + (d/2)² )!/2 - Lo )²
5) k (h? + (d/2)² - Lo )?
6) k ( ( h² + (d/2)² )'/2 - Lo )?
Part (d) Calculate the total potential energy, in joules, stored in the elastic bands before the cage is released.
Numeric : A numeric value is expected and not an expression.
U =
Part (e) Calculate the maximum height, in meters, of the ride.
Numeric : A numeric value is expected and not an expression.
hf =
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