Problem 4 Let V be the span of the following vectors F 3 V1 = U2 = -2 2 V3 = 8 6 U4 = V5 = V6 = -1 5 1. Why these six vectors are NOT linearly independent? Explain? 2. Find a basis for V = span{v1, U2, U3, U4: U5, U6). 3. What is the dimension of V? Why? The following vector is in V, write it as a linear combination of the basis vectors you found in part (2). u= [2 2 2 10]"

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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Base of a vector space
### Problem 4

**Let \( V \) be the span of the following vectors:**

\[ v_1 = \begin{bmatrix} -1 \\ 1 \\ 3 \\ 5 \end{bmatrix}, v_2 = \begin{bmatrix} -2 \\ 1 \\ 2 \\ -4 \end{bmatrix}, v_3 = \begin{bmatrix} -4 \\ -1 \\ 8 \\ 6 \end{bmatrix}, v_4 = \begin{bmatrix} 0 \\ 1 \\ 1 \\ 1 \end{bmatrix}, v_5 = \begin{bmatrix} -2 \\ 0 \\ 6 \\ 2 \end{bmatrix}, v_6 = \begin{bmatrix} 1 \\ -1 \\ 5 \\ 7 \end{bmatrix} \]

1. **Why these six vectors are NOT linearly independent? Explain?**

2. **Find a basis for \( V = \text{span} \{ v_1, v_2, v_3, v_4, v_5, v_6 \} \).**

3. **What is the dimension of \( V \)? Why? The following vector is in \( V \), write it as a linear combination of the basis vectors you found in part (2).**

\[ u = \begin{bmatrix} 2 \\ -2 \\ 2 \\ 10 \end{bmatrix}^T \]

**Solution 4:**

(Note: This problem set includes a series of vectors and questions related to linear independence, finding a basis, and dimensionality within the context of vector spaces.)

### Explanation of Linear Independence

Linear independence of vectors means that no vector in the set can be written as a linear combination of the others. If the vectors are not linearly independent, it means there exists a non-trivial linear combination of these vectors that equals the zero vector.

### Visual Explanation of Basis and Dimension

Finding a basis for a vector space generally involves determining the set of linearly independent vectors that span the entire vector space. The dimension of the space is the number of vectors in the basis.

### Detailed Analysis Steps for Solutions

- **Step 1: Check Linear Independence**
  - Construct a matrix with vectors \( v_1, v_2, v_3, v_4, v_5
Transcribed Image Text:### Problem 4 **Let \( V \) be the span of the following vectors:** \[ v_1 = \begin{bmatrix} -1 \\ 1 \\ 3 \\ 5 \end{bmatrix}, v_2 = \begin{bmatrix} -2 \\ 1 \\ 2 \\ -4 \end{bmatrix}, v_3 = \begin{bmatrix} -4 \\ -1 \\ 8 \\ 6 \end{bmatrix}, v_4 = \begin{bmatrix} 0 \\ 1 \\ 1 \\ 1 \end{bmatrix}, v_5 = \begin{bmatrix} -2 \\ 0 \\ 6 \\ 2 \end{bmatrix}, v_6 = \begin{bmatrix} 1 \\ -1 \\ 5 \\ 7 \end{bmatrix} \] 1. **Why these six vectors are NOT linearly independent? Explain?** 2. **Find a basis for \( V = \text{span} \{ v_1, v_2, v_3, v_4, v_5, v_6 \} \).** 3. **What is the dimension of \( V \)? Why? The following vector is in \( V \), write it as a linear combination of the basis vectors you found in part (2).** \[ u = \begin{bmatrix} 2 \\ -2 \\ 2 \\ 10 \end{bmatrix}^T \] **Solution 4:** (Note: This problem set includes a series of vectors and questions related to linear independence, finding a basis, and dimensionality within the context of vector spaces.) ### Explanation of Linear Independence Linear independence of vectors means that no vector in the set can be written as a linear combination of the others. If the vectors are not linearly independent, it means there exists a non-trivial linear combination of these vectors that equals the zero vector. ### Visual Explanation of Basis and Dimension Finding a basis for a vector space generally involves determining the set of linearly independent vectors that span the entire vector space. The dimension of the space is the number of vectors in the basis. ### Detailed Analysis Steps for Solutions - **Step 1: Check Linear Independence** - Construct a matrix with vectors \( v_1, v_2, v_3, v_4, v_5
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