Problem 4- Forces and Vectors: view of a force table is shown below as well as a free body diagram. F,-5N and points in the *x-direction, and F-3N and points in the +y-direction. We can use vectors to represent forces. A top-down F2 F2 3N F1 5N F1 F3 ? A. What force (F,) is required to bring this system to equilibrium? (Recall that the X-component of this force is equal to F, and the y-component is equal to F,) 3-5=-2 F2 7 T-T. F3 -2 F1 B. At what angle (labeled 0 in the diagram) must the force be placed in order to bring the system to equilibrium? (Recall that the inverse tangent function can be used to calculate the angle given the x- and y-components).

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We can use vectors to represent forces. A top-down
Problem 4- Forces and Vectors:
view of a force table is shown below as well as a free body diagram. F,-5N and points in the
*x-direction, and F,-3N and points in the +y-direction.
F2
F2-3N
F1 5N
F1
*F3=?
-1
A.
What force (F,) is required to bring this system to equilibrium? (Recall that the
X-component of this force is equal to F, and the y-component is equal to F,)
3-S=-2
7, T-T
F3 -2
B. At what angle (labeled 0 in the diagram) must the force be placed in order to
bring the system to equilibrium? (Recall that the inverse tangent function can be used to
calculate the angle given the x- and y-components).
Transcribed Image Text:We can use vectors to represent forces. A top-down Problem 4- Forces and Vectors: view of a force table is shown below as well as a free body diagram. F,-5N and points in the *x-direction, and F,-3N and points in the +y-direction. F2 F2-3N F1 5N F1 *F3=? -1 A. What force (F,) is required to bring this system to equilibrium? (Recall that the X-component of this force is equal to F, and the y-component is equal to F,) 3-S=-2 7, T-T F3 -2 B. At what angle (labeled 0 in the diagram) must the force be placed in order to bring the system to equilibrium? (Recall that the inverse tangent function can be used to calculate the angle given the x- and y-components).
Expert Solution
Step 1

The forces F1 and F3 point in the +x and +y directions respectively.

F1 has a magnitude of 5 N and F3 has a magnitude of 3 N. There is another force F2, acting on some arbitrary angle to the negative y axis.

In order for this system of 3 forces to be in equilibrium, the net force acting on the system should be equal to zero.

The net force on the system can be thought as components of forces, acting along the x and y directions. Since F1 is along the x direction and F3 is along the y direction.

F2 is at some angle θ with the negative y axis. This force can be resolved into component forces along the x and y directions as

F2y=F2cosθ, along negative y axisF2x=F2sinθ, along negative x axis

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