Problem 4: A rectangular conducting loop has sides a = 0.045 m, sides b = 0.15 m, and resistance R = 55 22. It moves into a magnetic field of magnitude B = 1.09 T with speed v= 9.5 m/s. Refer to the diagram. a b 7 X X X X X X X X X X X X X X X X X X ххх X X X X X X X X B X X X X X X X xx 100 X X X X X
Problem 4: A rectangular conducting loop has sides a = 0.045 m, sides b = 0.15 m, and resistance R = 55 22. It moves into a magnetic field of magnitude B = 1.09 T with speed v= 9.5 m/s. Refer to the diagram. a b 7 X X X X X X X X X X X X X X X X X X ххх X X X X X X X X B X X X X X X X xx 100 X X X X X
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter30: Faraday's Law
Section: Chapter Questions
Problem 34AP: Why is the following situation impossible? A conducting rectangular loop of mass M = 0.100 kg,...
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Question
Part (a) Find the current, Ii, in amperes, flowing in the loop as it enters the magnetic field.
Ii = ______
Part (b) Find the current, If, in amperes, in the loop as it leaves the magnetic field. It leaves at the same speed it enters.
If = ______
![Problem 4: A rectangular conducting loop has sides a = 0.045 m, sides b = 0.15 m, and resistance R
= 55 22. It moves into a magnetic field of magnitude B = 1.09 T with speed v = 9.5 m/s. Refer to the
diagram.
T
a
b
X X X
X
X X X
ххххх
X X
ххххх
ххххх
xx
13
X X X
B
xx
XX
X
X
X X X
X
xx
X X
X
xx
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff062ae38-2401-46ec-b1b4-5c5b28807dc0%2F4904a8ce-dde6-48cf-ae73-92820e3d604f%2F9pzx66s_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 4: A rectangular conducting loop has sides a = 0.045 m, sides b = 0.15 m, and resistance R
= 55 22. It moves into a magnetic field of magnitude B = 1.09 T with speed v = 9.5 m/s. Refer to the
diagram.
T
a
b
X X X
X
X X X
ххххх
X X
ххххх
ххххх
xx
13
X X X
B
xx
XX
X
X
X X X
X
xx
X X
X
xx
X
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Step 1: Determine the given data in the step :
VIEWStep 2: Determine the formulation for current on entering the field in the step :
VIEWStep 3: Determine the current on entering the field through calculations in the step :
VIEWStep 4: Determine the current on leaving the field through calculations in the step :
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