Problem 4: A ray of light is incident on an air/water interface. The ray makes an angle of 01 = 43 degrees with respect to the normal of the surface. The index of the air is n = 1 while water is n₂ = 1.33. 01 n1 ་ྲ n2 02 @theexpertta.com - tracking id: 6C65-4A-91-4F-8E13-45921. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. Part (a) Choose an expression for the angle (relative to the normal to the surface) for the ray in the water, 02. Correct Answer 6₁₂ = asin (sin(₁) n2 Grade Summary Deduction for Final Submission Student Final Submission 6₂ = asin (sin(₁) n2' 0% Deductions for Incorrect Submissions, Hints and Feedback [?] 0% Student Grade = 10000 = 100% Feedback Correct! Submission History All Date times are displayed in Pacific Standard Time.Red submission date times indicate late work. Date 1 May 02, 2024 Time 3:59 PM Answer n1 8₂ = sin(0₁) n2 2 May 02, 2024 3:59 PM 02 = asin (sin (6) m) 02 = = 19.19 4 = 90 - 01 Part (b) Numerically, what is the angle in degrees? * Attempts Remain Hints Feedback Note: Feedback not accessed. Part (c) Write an expression for the reflection angle 4, with respect to the surface. ✓ Correct! Part (d) Numerically, what is this angle in degrees? 4 = 56.00 * Attempts Remain

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