PROBLEM 36: A triangular lot was formed by three straight lines. Bearing of line AB is N45°Ė and is 160 m long; line AC and BC is 190 m long. Point E is 100 m from A on side AB connects point D on side AC which divides the area, making area AED to be 2/5 of the whole area. Find the distance DE. c. 120.6 m d. 109.1 m c. 99.01 m d. 88.14 m

3. The Distance from A andB to a point C are measured with the following results; BC 754,46 m, AC-2962.43 m. Assuming C to be to the right of AB and given the following coordinates, determine The angles of the triangles ABC, N(m) E(m) 82282.61 28905.74 79634.85 29974.47

E Compute the area bounded by the polygon A, B, C, D, E, F and the circular segment area bounded by the curve EF and line EF. R Angle theta = As given on Carmen G Point X- ft Y - ft A 500 500 B 1000 600 C 1500 1100 1300 2000 А E 700 1800 F 300 1000 Compute the area bounded by A, B, C, D, E, Arch EF and closing on A (The whole parcel in the blue lines). Report area in Acres with 4 decimals precision. Angle theta = 44° 00' 00"