Problem 3.with their central axes along the x-axis.• Ring 1 has a radius R₁ = 3 cm and a charge Q₁= 46 PC uniformly distributed over the ring.• Ring 2 has a radius R₂ = 2 cm and linearcharge density X2 = 41 pc/m.• The rings are separated by a distance d = 30cm.R₁Ring 1OE₁ =OE₁ =5.y [cm]4.point A is:Ē₁-The figure shows two rings1.The magnitude of the electricfield created by ring 1 at point A can be calculatedby:OE₁ =Coulombs.Q₂ =OE₂ =R₁OE₂ =--A(9x109) (46-10-12)-(3-10-2)((3-10-2)²+(3-10-2)2) 1.52.The value of the magnitude of theelectric field created by ring 1 at point A is:E₁ =[N/C]3.field created by ring 1 at point A?ORightOLeftOupOdown(9x109) (46-10-12)-(3-10-2)((3-10-2)²+(3-10-2)2)0.5(9x109) (46-10-12). (3)((3)²+(3)2)1.5d+What is the direction of the electricRing 2R₂2The electric field created by ring 1 at[C][N/C]Calculate the total charge of ring 2 in6.The magnitude of the electricfield created by ring 2 at point A can be calculatedby:OE₂=(9x109) (5.15x10-12).(0.27)((0.27)²+(2-10-2)2) 1.5(9x109) (5.15×10−12).(0.27)((0.27)²+(2-10-2)2) 0.5(9x109) (5.15×10-¹²).(0.27)((0.27)²+(2)2)0.57.If the magnitude of the electric fieldcreated by ring 2 at point A is equal to E₂ =6.31x10-13 [N/C], find the electric field vectorcreated by the ring 2 at point A.Ē₂+[N/C]

Problem 3. with their central axes along the x-axis. • Ring 1 has a radius R₁ = 3 cm and a charge Q₁ = 46 PC uniformly distributed over the ring. • Ring 2 has a radius R₂ = 2 cm and linear charge density X2 = 41 pc/m. •The rings are separated by a distance d = 30 cm. R₁ Ring 1 OE₁= OE₁ = Oright OLeft Oup Odown 5. 1. The magnitude of the electric field created by ring 1 at point A can be calculated by: OE₁ = y [cm] 4. point A is: Ē₁ The figure shows two rings R₁ Coulombs. Q₂ = OE₂= 2. The value of the magnitude of the electric field created by ring 1 at point A is: E₁ = [N/C] 3. field created by ring 1 at point A? OE₂ = -1 A (9x109) (46-10-12)-(3-10-²) ((3-10-2)2+(3-10-2)2)1.5 (9x109) (46-10-12)-(3-10-2) ((3-10-2)2+(3-10-2)2)0.5 (9x109) (46-10-12). (3) ((3)²+(3)2)1.5 d i + What is the direction of the electric Ring 2 The electric field created by ring 1 at [C] R₂ [N/C] Calculate the total charge of ring 2 in 6. The magnitude of the electric field created by ring 2 at point A can be calculated by: OE₂ = (9x109) (5.15× 10-12). (0.27) ((0.27)²+(2-10-2)2) 1.5 (9x109) (5.15x10-12). (0.27) ((0.27)²+(2-10-2)2) 0.5 (9x109) (5.15x10-12).(0.27) ((0.27)²+(2)2)0.5 7. If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 6.31x10-13 [N/C], find the electric field vector created by the ring 2 at point A. Ē₂ = 2 + [N/C]

Problem 3. with their central axes along the x-axis. • Ring 1 has a radius R₁ = 3 cm and a charge Q₁ = 46 PC uniformly distributed over the ring. • Ring 2 has a radius R₂ = 2 cm and linear charge density X2 = 41 pc/m. •The rings are separated by a distance d = 30 cm. R₁ Ring 1 OE₁= OE₁ = Oright OLeft Oup Odown 5. 1. The magnitude of the electric field created by ring 1 at point A can be calculated by: OE₁ = y [cm] 4. point A is: Ē₁ The figure shows two rings R₁ Coulombs. Q₂ = OE₂= 2. The value of the magnitude of the electric field created by ring 1 at point A is: E₁ = [N/C] 3. field created by ring 1 at point A? OE₂ = -1 A (9x109) (46-10-12)-(3-10-²) ((3-10-2)2+(3-10-2)2)1.5 (9x109) (46-10-12)-(3-10-2) ((3-10-2)2+(3-10-2)2)0.5 (9x109) (46-10-12). (3) ((3)²+(3)2)1.5 d i + What is the direction of the electric Ring 2 The electric field created by ring 1 at [C] R₂ [N/C] Calculate the total charge of ring 2 in 6. The magnitude of the electric field created by ring 2 at point A can be calculated by: OE₂ = (9x109) (5.15× 10-12). (0.27) ((0.27)²+(2-10-2)2) 1.5 (9x109) (5.15x10-12). (0.27) ((0.27)²+(2-10-2)2) 0.5 (9x109) (5.15x10-12).(0.27) ((0.27)²+(2)2)0.5 7. If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 6.31x10-13 [N/C], find the electric field vector created by the ring 2 at point A. Ē₂ = 2 + [N/C]