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Problem 3. The rate of consumption of hamburgers in Wyoming (in millions of hamburgers per year) since 1960 is given approximately by the function H(t)=t+where t = 0 corresponds to 1960. Determine the average number of hamburgers per year eaten in Wyoming during the ten years 1970 to 1980.

Problem 3. The rate of consumption of hamburgers in Wyoming (in millions of hamburgers per year) since 1960 is given approximately by the function H(t)=t+where t = 0 corresponds to 1960. Determine the average number of hamburgers per year eaten in Wyoming during the ten years 1970 to 1980.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem 3 The rate of consumption of hamburgers in Wyoming (in millions of hamburgers per year) since 1960 is given approximately by the function \( H(t) = \frac{1}{10} t^2 + \frac{12}{5} \) where \( t = 0 \) corresponds to 1960. **Task:** Determine the average number of hamburgers per year eaten in Wyoming during the ten years 1970 to 1980. **Explanation:** - \( H(t) \) represents the rate of hamburger consumption, measured in millions of hamburgers per year. - The variable \( t \) represents the number of years since 1960. - You need to calculate the average consumption over the interval \( t = 10 \) (corresponding to 1970) to \( t = 20 \) (corresponding to 1980). **Steps to Solve:** 1. Integrate \( H(t) \) from \( t = 10 \) to \( t = 20 \). 2. Divide the result by the length of the interval (which is 10 years). This problem requires using integral calculus to find the total consumption over the given period and then averaging it over the number of years.
Transcribed Image Text:### Problem 3 The rate of consumption of hamburgers in Wyoming (in millions of hamburgers per year) since 1960 is given approximately by the function \( H(t) = \frac{1}{10} t^2 + \frac{12}{5} \) where \( t = 0 \) corresponds to 1960. **Task:** Determine the average number of hamburgers per year eaten in Wyoming during the ten years 1970 to 1980. **Explanation:** - \( H(t) \) represents the rate of hamburger consumption, measured in millions of hamburgers per year. - The variable \( t \) represents the number of years since 1960. - You need to calculate the average consumption over the interval \( t = 10 \) (corresponding to 1970) to \( t = 20 \) (corresponding to 1980). **Steps to Solve:** 1. Integrate \( H(t) \) from \( t = 10 \) to \( t = 20 \). 2. Divide the result by the length of the interval (which is 10 years). This problem requires using integral calculus to find the total consumption over the given period and then averaging it over the number of years.
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