Same problem is already solved on bartleby. Only 20 mm dimension is there instead of 21 mm. You can use it for reference. I have attached that solution also PROBLEM 3.20 mm35 mm20 mmThe beam has a thin-walled cross section as shownand the wall thickness is 4 mm.For a vertical shear of 5000 N, (a) determine andsketch shear flow distribution (b) determine themaximum shear stress in the beam.28 mm75 mm 11:07 PM A O4GVoLTE21O Litewww.bartleby.com/que4Q SEARCH & ASK턺 CHATVX MATH SOLVGiven data :Given thin welled Cross section:28 mm2135 mm2immwall thicknepsventical Shear ce = 5000N= 4mm->Step 2: Shear stress distributionstep 1: shear blow distribution.FASWe know shear stress: Tmax =I bxTmaxbx* In blanged beams width changes suddenly. so there.will be sudden charyeinTmax diagram.Shear Stics DiagamCross secton->Step 3: Maximum shear stressStep 2: sheor stress (Max)Length ob inclined member: J28+21²A- 2(35 XA) +(35 x4)+ '(75 x 4)1: a() +() + (75**)= 35 mm: 720 mm?=15 2213mm4Y = = 14 mm28Tman=5000X720 x 14A13.89 N(mm?Ibx15221.3X 8Rate this solution

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PROBLEM 3. 20 mm 35 mm 20 mm The beam has a thin-walled cross section as shown and the wall thickness is 4 mm. For a vertical shear of 5000 N, (a) determine and sketch shear flow distribution (b) determine the maximum shear stress in the beam. 28 mm 75 mm

PROBLEM 3. 20 mm 35 mm 20 mm The beam has a thin-walled cross section as shown and the wall thickness is 4 mm. For a vertical shear of 5000 N, (a) determine and sketch shear flow distribution (b) determine the maximum shear stress in the beam. 28 mm 75 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Same problem is already solved on bartleby. Only 20 mm dimension is there instead of 21 mm. You can use it for reference. I have attached that solution also

PROBLEM 3.
20 mm
35 mm
20 mm
The beam has a thin-walled cross section as shown
and the wall thickness is 4 mm.
For a vertical shear of 5000 N, (a) determine and
sketch shear flow distribution (b) determine the
maximum shear stress in the beam.
28 mm
75 mm

11:07 PM A O
4G
Vo
LTE
21
O Lite
www.bartleby.com/que
4
Q SEARCH & ASK
턺 CHAT
VX MATH SOLV
Given data :
Given thin welled Cross section:
28 mm
21
35 mm
2imm
wall thickneps
ventical Shear ce = 5000N
= 4mm
->
Step 2: Shear stress distribution
step 1: shear blow distribution.
FAS
We know shear stress: Tmax =
I bx
Tmax
bx
* In blanged beams width changes suddenly. so there.
will be sudden charye
in
Tmax diagram.
Shear Stics Diagam
Cross secton
->
Step 3: Maximum shear stress
Step 2: sheor stress (Max)
Length ob inclined member: J28+21²
A- 2(35 XA) +(35 x4)+ '(75 x 4)
1: a() +() + (75**)
= 35 mm
: 720 mm?
=15 2213mm4
Y = = 14 mm
28
Tman=
5000X720 x 14
A13.89 N(mm?
Ibx
15221.3X 8
Rate this solution

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