Problem #3: Write code that divides a positive number n in half until the resulting number is less than 1. For this exercise, use a method that doesn't require you to convert the integer n to a different data type. For example, if n = 5, the first time through the loop should result in 2.5, the second time through should result in 1.25, and the third time through should result in 0.625. The loop should not be executed a forth time since 0.625 < 1. (a) If n = 20000, how many times through the loop will the code run? (b) Determine the missing line of code which produces the output shown. Type the missing line of code into the answer box below. n=12345 while n>=10: (missing line) n=n//10 print (r) print (n)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Problem #3: Write code that divides a positive number n in half until the resulting number is less than 1. For
this exercise, use a method that doesn't require you to convert the integer n to a different data
type. For example, if n = 5, the first time through the loop should result in 2.5, the second time
through should result in 1.25, and the third time through should result in 0.625. The loop should
not be executed a forth time since 0.625 < 1.
(a) If n = 20000, how many times through the loop will the code run?
(b) Determine the missing line of code which produces the output shown. Type the missing line
of code into the answer box below.
n=12345
while n>=10:
5
4
3
print (n)
HN W
2
(missing line)
n=n//10
1
print (r)
Transcribed Image Text:Problem #3: Write code that divides a positive number n in half until the resulting number is less than 1. For this exercise, use a method that doesn't require you to convert the integer n to a different data type. For example, if n = 5, the first time through the loop should result in 2.5, the second time through should result in 1.25, and the third time through should result in 0.625. The loop should not be executed a forth time since 0.625 < 1. (a) If n = 20000, how many times through the loop will the code run? (b) Determine the missing line of code which produces the output shown. Type the missing line of code into the answer box below. n=12345 while n>=10: 5 4 3 print (n) HN W 2 (missing line) n=n//10 1 print (r)
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