Problem #3 The figure below shows a compound open-channel cross- section. Determine the energy correction factor a using equation below. [v³dA A Assume uniform velocities within the subsections. (3) 1 A₁ = 1200 ft² Q₁ = 1073 cfs (n = 0.04) 80 ft->|< α= 2 1 AV 3 A₂ = 2500 ft² Q₂ = 8854 cfs (n = 0.02) -100 ft- | A3 = 1200 ft² Q3 = 1073 cfs (n=0.04) 80 ft- 125 ft - 110 ft - 100 ft
Problem #3 The figure below shows a compound open-channel cross- section. Determine the energy correction factor a using equation below. [v³dA A Assume uniform velocities within the subsections. (3) 1 A₁ = 1200 ft² Q₁ = 1073 cfs (n = 0.04) 80 ft->|< α= 2 1 AV 3 A₂ = 2500 ft² Q₂ = 8854 cfs (n = 0.02) -100 ft- | A3 = 1200 ft² Q3 = 1073 cfs (n=0.04) 80 ft- 125 ft - 110 ft - 100 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Problem #3
The figure below shows a compound open-channel cross-
section. Determine the energy correction factor a using equation
below.
fuºda
v³ d A
A
Assume uniform velocities within the subsections.
(3)
1
A₁ = 1200 ft²
Q₁ = 1073 cfs
(n = 0.04)
80 ft->|<
α=
2
1
AV 3
A₂ = 2500 ft²
Q₂ = 8854 cfs
(n= 0.02)
-100 ft-
| A3 = 1200 ft²
Q3 = 1073 cfs
(n = 0.04)
80 ft-
125 ft
- 110 ft
- 100 ft
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