Problem # 3 Note: use 3 decimal places A column is a built up from 4 - 300mm x 18 mm plates, welded to form a box section having a width of 336mm along x-axis and a depth of300mm along the y- axis. Unbraced column length with respect to the x-axis is 12m. With respect to y-axis, the column is braced at third points so that the un- braced length is 4m. Assumed pinned-ends for both axis. Sidesway is prevented. Steel yields stress: Fy 248MPA Modulus Elasticity: Es = 200GPa a. Compute the effective slenderness ratio of the built up section. b. Compute the axial load capacity of the built up section.

Problem # 3 Note: use 3 decimal places A column is a built up from 4 - 300mm x 18 mm plates, welded to form a box section having a width of 336mm along x-axis and a depth of300mm along the y- axis. Unbraced column length with respect to the x-axis is 12m. With respect to y-axis, the column is braced at third points so that the un- braced length is 4m. Assumed pinned-ends for both axis. Sidesway is prevented. Steel yields stress: Fy 248MPA Modulus Elasticity: Es = 200GPa a. Compute the effective slenderness ratio of the built up section. b. Compute the axial load capacity of the built up section.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please answer. Ty
What is the meaning of Pre-History?
TOPIC : TRUSS ADALYSIS (USWE METHOO OF JONTS) complete one tabe. EXPERIM ENTA L OMPUTED VALUES TRIALS % EPOR VALUES, N TRIAL #I RA=O4459 K9 (6.5258 Ikg load at pt-C KF :0-3345 ka 3.2781 -2.99N (T) -4.39 N (T) (c) BOTTOM CADRO WEB TOP CHORD 6-17 H (C) B P16URE OF TROSS A
! Engineering Management ! Make an example of a QUALITY PLAN. Civil Engineer
SOLVE FOR THE FORCE IN MEMBERS AB, AC, BC, CD, BD, BE, DE, DF & EF. SHOW SOLUTIONS CLEARLY USING METHOD OF JOINTS AND WRITE WELL ALSO SEE LINK UNDER WEEK7 0.8m 2.4m -6KN MEMBER AB AC BC CD BD BE 2m ED DF EF 1m 8KN Av REACTION hinge) EX REACTION @roller) 3m SUMMARY OF RESULTS FORCE 1m 10KN 2.4m 3KN NATURE(I or C)
Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
figure A 2m """" B 2 m C ** 2 m E 4 m D 700 N 500 N 2 of 2 > ▼ Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. EF FG ODF П П П □ DE AB ВС BC AG CG CD BG CF Submit Provide Feedback Request Answer
Structure RA R RE, VL MA, MC V B. VD nd Mm Hw. Draw I L far
Q3: А- Oesign a rectangular beam with b = 350 mm, h = 625 mm as shown below. Use f! = 30 MPa, fy = 375 MPa and Ø18 mm for %3D fongitudinal reinforcement. Two lavers of tension reinforcement. PE45 kN Wu,-25 kN/m WUT14 kN/m D.L babulb 5 m B- Check the design of the singly reinforced beam shown below, if fc = 20 MPa and fy = 420 MPa, 030 mm for tension. Why? %3D sed edr arlagead iso t 430 mm 100 mm 300 mm
For the given loaded truss, the allowable tensile stress in any member is up to 800 MPa while the allowable compressive stress is up to 650 MPa. The reduced stress in compression is specified to reduce the danger of buckling. Determine the minimum cross-sectional area of member CE. Solve with complete solution and proper FBD.
Hand written and clean solution please
PLATE NO 3 Method of Sections Chapter 5 Problem 5-2 Page 76 Using the method of sections, determine the kind and amount of stress in the following members of the truss shown in figure P5-2 (page 76). U:U2 UıL2 LIL2 U2U3 U2L3 L2L3 1000lb 1000lb U3 1000lb 1000lb 1000lb U2 U4 500lb Ui 500lb h=20ft Us Lo L1 L2 L3 L4 Ls RAV 6 panels at 10' = 60 ft RBv