Problem 3: Let T: V → V be a linear map, let v € V, and let W be the T-cyclic subspace of V generated by v. a.) For any u E V, show that u € W if and only if there exists a polynomial f(t) such that u = f(T)v. b.) Suppose dim W = k. Show that f(t) can be taken to have degree at most k.

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Problem 3: Let T: V → V be a linear map, let v € V, and let W be the T-cyclic
subspace of V generated by v.
a.) For any u € V, show that u € W if and only if there exists a polynomial f(t)
such that u = f(T)v.
b.) Suppose dim W = k. Show that f(t) can be taken to have degree at most k.
Transcribed Image Text:Problem 3: Let T: V → V be a linear map, let v € V, and let W be the T-cyclic subspace of V generated by v. a.) For any u € V, show that u € W if and only if there exists a polynomial f(t) such that u = f(T)v. b.) Suppose dim W = k. Show that f(t) can be taken to have degree at most k.
Expert Solution
Step 1

Given that T:VV be a linear map and vV.

Given that W be the T-cyclic subspace generated by v.

We know that a subspace W is a T-cyclic subspace generated by v if:

W=spanv,Tv,T2v,.

(a)

Let uV be an arbitrary element.

Forward proof:

Suppose that uW.

Since W be the T-cyclic subspace generated by v and hence W=spanv,Tv,T2v,, therefore uspanv,Tv,T2v,.

Therefore there exists a largest natural number n and c0,c1,,cnF such that:

u=c0v+c1Tv+c2T2v++cnTnv=c0I+c1T+c2T2++cnTnv.

Now suppose fT=c0I+c1T+c2T2++cnTn, which is a polynomial.

Therefore there exists a polynomial fT such that u=fTv.

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