Problem #3Here.we want to find the centroidSince it's symmetric about Z, X=0, Y=0.So, we need to find 2 only.first step, let's takez = 6.25 (0.25 – v²)Again, as athin disk, with a thickness dz.a0.3 m(1) Find the Coordinates of the centro idof this disk1 m(2) Find the volume of this disk.(3) Determime the whole volume.(4) Determ ne 2.0.5 m

Given data Z=6.250.25-y2dZ=6.250-2ydydZ=-12.50ydy 1} The centroid of disk =Z1

Problem #3 Here. we want to find the centroic Since it's symmetric about z, x=0, Y=o. So, we need to find Z only. first step, let's take z = 6.25 (0.25 – y²) Again, as thin disk, with a thickness dz. a 0.3 m (1) Find the Coordinates of the centro id of this disk. 1 m (a) Find the volume of this disk. (3) Determine the whole volume. (4) Determne 2. 0.5 m

Problem #3 Here. we want to find the centroic Since it's symmetric about z, x=0, Y=o. So, we need to find Z only. first step, let's take z = 6.25 (0.25 – y²) Again, as thin disk, with a thickness dz. a 0.3 m (1) Find the Coordinates of the centro id of this disk. 1 m (a) Find the volume of this disk. (3) Determine the whole volume. (4) Determne 2. 0.5 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Dimensional homogeneity

The term dimensional homogeneity means that in an equation, the dimensions of each term on both sides are equal, which means the dimensions of the left-hand side (LHS) of an equation are similar to the dimensions of the right-hand side (RHS). For a dimensionally homogeneous equation, the powers of fundamental dimensions will be identical on both sides of the equation.

Question

Problem #3
Here.
we want to find the centroid
Since it's symmetric about Z, X=0, Y=0.
So, we need to find 2 only.
first step, let's take
z = 6.25 (0.25 – v²)
Again, as a
thin disk, with a thickness dz.
a
0.3 m
(1) Find the Coordinates of the centro id
of this disk
1 m
(2) Find the volume of this disk.
(3) Determime the whole volume.
(4) Determ ne 2.
0.5 m

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