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Problem 3: Friends and Relations Select/write a solution to each of these problems using relational and logical operators. Do not use any if statements! Rule 1: If I see a friend, I greet them. (Friends can be seen more than once in the same input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them. Rule 3: The input consists of the names of the people I meet represented as String data Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations not just one of them. odd number of people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends = (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three = input() == "David" AND input() == "David" AND input() == "David" print one or two or three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends boolean oddFriends oddFriends = (input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David") print oddFriends

Problem 3: Friends and Relations Select/write a solution to each of these problems using relational and logical operators. Do not use any if statements! Rule 1: If I see a friend, I greet them. (Friends can be seen more than once in the same input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them. Rule 3: The input consists of the names of the people I meet represented as String data Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations not just one of them. odd number of people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends = (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three = input() == "David" AND input() == "David" AND input() == "David" print one or two or three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends boolean oddFriends oddFriends = (input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David") print oddFriends

C++ Programming: From Problem Analysis to Program Design
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter5: Control Structures Ii (repetition)
Section: Chapter Questions
Problem 20PE: When you borrow money to buy a house, a car, or for some other purpose, you repay the loan by making...
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input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them Rule 3: The input consists of the names of the people I meet represented as String data Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations, not just one of them. Friend: "David" Input: 5 people Output: true iff I greet an odd number of O O people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three=input() == "David" AND input() == "David" AND input() == "David" print one OR two OR three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends
Transcribed Image Text:input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them Rule 3: The input consists of the names of the people I meet represented as String data Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations, not just one of them. Friend: "David" Input: 5 people Output: true iff I greet an odd number of O O people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three=input() == "David" AND input() == "David" AND input() == "David" print one OR two OR three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends
Problem 3: Friends and Relations Select / write a solution to each of these problems using relational and logical operators. Do not use any if statements! Rule 1: If I see a friend, I greet them. (Friends can be seen more than once in the same input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them. Rule 3: The input consists of the names of the people I meet represented as String data. Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations, not just one of them. odd number of people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends = (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three = input() == "David" AND input() == "David" AND input() == "David" print one OR two OR three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends boolean oddFriends oddFriends (input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David") print oddFriends
Transcribed Image Text:Problem 3: Friends and Relations Select / write a solution to each of these problems using relational and logical operators. Do not use any if statements! Rule 1: If I see a friend, I greet them. (Friends can be seen more than once in the same input.) Rule 2: If a person doesn't have the name of a friend, I do not greet them. Rule 3: The input consists of the names of the people I meet represented as String data. Note: All output should be true if and only if a certain condition occurs. Your code must return true for all situations where that condition occurs, not just some of them. Similarly, your code must return false for all situations where the condition does not occur. For example, if I have two friends named "Abby" and "George", I would greet both of them if I saw "Abby" first, then "George". But, I would also greet them both if I saw "George" first, then "Abby". My code would need to print true in both of those situations, not just one of them. odd number of people. (true if 1, 3, or 5 people, false otherwise) boolean oddFriends oddFriends = (input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David" AND input() EQ "David") print oddFriends boolean one, three, five one =input() == "David" two =input() == "David" AND input() == "David" three = input() == "David" AND input() == "David" AND input() == "David" print one OR two OR three boolean oddFriends oddFriends = (input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David" OR input() EQ "David") print oddFriends boolean oddFriends oddFriends (input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David" XOR input() EQ "David") print oddFriends
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