Problem 3: Find two roots of the equation cos(r)e-2 sin(3 ln(2²)) = 0, on the interval [4, 10]. Explain how many decimal places you believe you have correct, and how many steps of the bisection method it took. Also include timing results for your calculations.
Problem 3: Find two roots of the equation cos(r)e-2 sin(3 ln(2²)) = 0, on the interval [4, 10]. Explain how many decimal places you believe you have correct, and how many steps of the bisection method it took. Also include timing results for your calculations.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Please use python and show the codes. The second picture is an example
![3. Problem 3: Find two roots of the equation
cos(x)e-2sin (3 ln(x²)) = 0,
on the interval [4, 10]. Explain how many decimal places you believe
you have correct, and how many steps of the bisection method it took.
Also include timing results for your calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe15a76cd-09c8-49fc-a97e-76e9013c0a32%2F7730f856-16fc-46fe-9bcc-8787202b3f16%2F4t9fibgd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Problem 3: Find two roots of the equation
cos(x)e-2sin (3 ln(x²)) = 0,
on the interval [4, 10]. Explain how many decimal places you believe
you have correct, and how many steps of the bisection method it took.
Also include timing results for your calculations.

Transcribed Image Text:import math
import time
#Want a root of f(x) = cos(x) x^2/2
def f(x):
return math.cos(x)
tol=10**-15
a
= 0.5
b = 1.5
Error =
c = math.nan
count = 0
(b-a)/2
tic time.time()
if f(a) f(b) < 0:
while (Error > tol) and (count < 1000):
X
c = (a+b)/2
if f(a) f(c) < 0:
b = c
elif f(b) f(c) < 0:
a = c
Error = (b-a)/2
count = count + 1
toc = time.time()
runTime = toc - tic
print ()
print (c)
print (Error)
print (f(c))
print (runTime)
print (count)
print()
Expert Solution
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