Problem 3 Electron's path in a uniform magnetic field An electron travels at 20 x 10 m/s in a plane perpendicular to a uniform 0.010 T magnetic field. Describe its path quantitatively. (Mass of an electron is 9.1 x 10-³¹kg, the charge in an electron is 16 x 10-¹C.) Approach
Problem 3 Electron's path in a uniform magnetic field An electron travels at 20 x 10 m/s in a plane perpendicular to a uniform 0.010 T magnetic field. Describe its path quantitatively. (Mass of an electron is 9.1 x 10-³¹kg, the charge in an electron is 16 x 10-¹C.) Approach
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:Problem 3
Electron's path in a uniform magnetic field
An electron travels at 20 x 10 m/s in a plane perpendicular to a uniform
0.010 T magnetic field. Describe its path quantitatively. (Mass of an electron is 9.1 x 10-³¹kg,
the charge in an electron is 16 x 10-¹C.)
Approach
The electron moves at speed v in a curved path and so must have a centripetal
acceleration a="We find the radius of curvature using Newton's second law. The
force is given by equation, F = qvB sin with sin 0=1, F =qvB.
We insert F and a into Newton's second law:
Σ F = ma
mv²
qvB=
mu
We solve for rand find
r =
qB
Since F is perpendicular to v, the magnitude of v
see that if = constant, then r = constant, and the
above.
doesn't change. From this equation we
curve must be a circle as we claimed
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