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Problem 3: Consider the linear program 2x1 + x2 max #1,2,3,4,5 ER x1 x1 -2x1 x1 After a few iterations of the simplex, we get the following subject to Z 1 0 0 0 + + x1 X2 0 0 1 0 0 0 " X2 x2 X2 X2 + " X3 X3 What is the optimal value of (5)? constraint that x₁ > 4. What is the new optimal value? 5 rhs + x4 " x3 4 1/2 3/2 0 8 1/2 1/2 0 3 1 -1/2 1/2 0 2 0 3/2 1/2 1 9 tableau: X4 + " basic variable x1 X2 X5 X5 X5 1 5 5 > 0 ||||| AV = (5) (6) Suppose that we would now like to solve (5) with the additional

Problem 3: Consider the linear program 2x1 + x2 max #1,2,3,4,5 ER x1 x1 -2x1 x1 After a few iterations of the simplex, we get the following subject to Z 1 0 0 0 + + x1 X2 0 0 1 0 0 0 " X2 x2 X2 X2 + " X3 X3 What is the optimal value of (5)? constraint that x₁ > 4. What is the new optimal value? 5 rhs + x4 " x3 4 1/2 3/2 0 8 1/2 1/2 0 3 1 -1/2 1/2 0 2 0 3/2 1/2 1 9 tableau: X4 + " basic variable x1 X2 X5 X5 X5 1 5 5 > 0 ||||| AV = (5) (6) Suppose that we would now like to solve (5) with the additional

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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TOPIC: Linear programming

Problem 3: Consider the linear program 2x1 + x2 max x1,x2,3,4,5 ER x1 X1 -2x1 X1 After a few iterations of the simplex, we get the following tableau: subject to + + 9 X2 x2 X2 x2 + X3 x3 + X4 Z X1 X2 x3 X4 X5 rhs 1 0 0 1/2 3/2 0 8 0 1 0 1/2 0 3 1/2 -1/2 0 0 1 1/2 0 2 0 0 0 3/2 1/2 1 9 X4 + X5 X5 basic variable X1 " x2 X5 5 5 0 (5) (6) What is the optimal value of (5)? Suppose that we would now like to solve (5) with the additional constraint that x₁ ≥ 4. What is the new optimal value?
Transcribed Image Text:Problem 3: Consider the linear program 2x1 + x2 max x1,x2,3,4,5 ER x1 X1 -2x1 X1 After a few iterations of the simplex, we get the following tableau: subject to + + 9 X2 x2 X2 x2 + X3 x3 + X4 Z X1 X2 x3 X4 X5 rhs 1 0 0 1/2 3/2 0 8 0 1 0 1/2 0 3 1/2 -1/2 0 0 1 1/2 0 2 0 0 0 3/2 1/2 1 9 X4 + X5 X5 basic variable X1 " x2 X5 5 5 0 (5) (6) What is the optimal value of (5)? Suppose that we would now like to solve (5) with the additional constraint that x₁ ≥ 4. What is the new optimal value?
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