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PROBLEM 3: Batch Distillation. A 750 kmol of an isopropanol (1)/1-butanol (2) hinary mixture containing 55.0 mol % 1-butanol is distilled in an atmospheric batch still. Per specifications, the final 1-butanol concentration of 95.0 mol % in the pot desired. Find the amount of distillate collected, the amount of waste left in the pot, and the average concentration of the distillats. Equilibrium Jata is given below for the binary system. Use an interpolation interval of 0.05. Equilibrium data for isopropanol (1)/1-butanol (2) binary system X1 0.000000 0.050000 0.100000 0.150000 0.200000 0.250000 0.300000 0.350000 0.400000 0.450000 0.500000 0.550000 0.600000 0.650000 0.700000 0.750000 0.800000 0.850000 0.900000 0.950000 1.000000 yı 0.000000 0.159122 0.288738 0.394530 0.482453 0.556395 0.619235 0.673141 0.719775 0.760425 0.796103 0.827614 0.855604 0.880600 0.903029 0.923248 0.941550 0.958183 0.973355 0.987221 1.000000

PROBLEM 3: Batch Distillation. A 750 kmol of an isopropanol (1)/1-butanol (2) hinary mixture containing 55.0 mol % 1-butanol is distilled in an atmospheric batch still. Per specifications, the final 1-butanol concentration of 95.0 mol % in the pot desired. Find the amount of distillate collected, the amount of waste left in the pot, and the average concentration of the distillats. Equilibrium Jata is given below for the binary system. Use an interpolation interval of 0.05. Equilibrium data for isopropanol (1)/1-butanol (2) binary system X1 0.000000 0.050000 0.100000 0.150000 0.200000 0.250000 0.300000 0.350000 0.400000 0.450000 0.500000 0.550000 0.600000 0.650000 0.700000 0.750000 0.800000 0.850000 0.900000 0.950000 1.000000 yı 0.000000 0.159122 0.288738 0.394530 0.482453 0.556395 0.619235 0.673141 0.719775 0.760425 0.796103 0.827614 0.855604 0.880600 0.903029 0.923248 0.941550 0.958183 0.973355 0.987221 1.000000

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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PROBLEM 3: Batch Distillation. A 750 kmol of an isopropanol (1)/1-butanol (2) hinary mixture containing 55.0 mol % 1-butanol is distilled in an atmospheric batch still. Per specifications, the final 1-butanol concentration of 95.0 mol % in the pot desired. Find the amount of distillate collected, the amount of waste left in the pot, and the average concentration of the distillat. Equilibrium data is given below for the binary system. Use an interpolation interval of 0.05. Equilibrium data for isopropanol (1)/1-butanol (2) binary system X1 0.000000 0.050000 0.100000 0.150000 0.200000 0.250000 0.300000 0.350000 0.400000 0.450000 0.500000 0.550000 0.600000 0.650000 0.700000 0.750000 0.800000 0.850000 0.900000 0.950000 1.000000 yı 0.000000 0.159122 0.288738 0.394530 0.482453 0.556395 0.619235 0.673141 0.719775 0.760425 0.796103 0.827614 0.855604 0.880600 0.903029 0.923248 0.941550 0.958183 0.973355 0.987221 1.000000
Transcribed Image Text:PROBLEM 3: Batch Distillation. A 750 kmol of an isopropanol (1)/1-butanol (2) hinary mixture containing 55.0 mol % 1-butanol is distilled in an atmospheric batch still. Per specifications, the final 1-butanol concentration of 95.0 mol % in the pot desired. Find the amount of distillate collected, the amount of waste left in the pot, and the average concentration of the distillat. Equilibrium data is given below for the binary system. Use an interpolation interval of 0.05. Equilibrium data for isopropanol (1)/1-butanol (2) binary system X1 0.000000 0.050000 0.100000 0.150000 0.200000 0.250000 0.300000 0.350000 0.400000 0.450000 0.500000 0.550000 0.600000 0.650000 0.700000 0.750000 0.800000 0.850000 0.900000 0.950000 1.000000 yı 0.000000 0.159122 0.288738 0.394530 0.482453 0.556395 0.619235 0.673141 0.719775 0.760425 0.796103 0.827614 0.855604 0.880600 0.903029 0.923248 0.941550 0.958183 0.973355 0.987221 1.000000
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