Problem 3 As a reminder, RN denotes the set of real sequences (uk)keN and S: RN -> (uk)KEN RN (Uk+1)kEN i.e. S((uk)keN) is the sequence whose kth term is uk+1 (for example, S((uk) kЄN)o is u₁ or S((uk)kEN)1 is u2....) Let RN 4: RN (uk)kENS((uk)kEN)-3(uk)kEN i.e. ((uk)ken) is the sequence whose kth term is uk+1-3uk- (1) Show that is a linear map. == (2) Let (ak) be the sequence, a = 3k for any k€ N. Show that (ak) is in Ker(). (3) Let (uk)ken be in Ker(). Show that uk = 3kuo.
Problem 3 As a reminder, RN denotes the set of real sequences (uk)keN and S: RN -> (uk)KEN RN (Uk+1)kEN i.e. S((uk)keN) is the sequence whose kth term is uk+1 (for example, S((uk) kЄN)o is u₁ or S((uk)kEN)1 is u2....) Let RN 4: RN (uk)kENS((uk)kEN)-3(uk)kEN i.e. ((uk)ken) is the sequence whose kth term is uk+1-3uk- (1) Show that is a linear map. == (2) Let (ak) be the sequence, a = 3k for any k€ N. Show that (ak) is in Ker(). (3) Let (uk)ken be in Ker(). Show that uk = 3kuo.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Problem 3 As a reminder, RN denotes the set of real sequences (uk)ken and
S :
RN
(uk)KEN
RN
(uk+1)KEN
i.e. S((uk)keN) is the sequence whose kth term is uk+1 (for example, S((uk)keN)o is u₁ or
S((uk)keN)1 is u2....) Let
4:
RN
RN
(uk) kEN S((uk)kEN)-3(uk) KEN
→
i.e. ((uk)keN) is the sequence whose kth term is uk+1-3uk
(1) Show that is a linear map.
(2) Let (ak)k be the sequence, ak
=
3k for any kN. Show that (ak)k is in Ker().
(3) Let (uk)ken be in Ker(). Show that uk = 3kuo.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85d6c9ff-164d-458c-bb12-814e2c6db1bb%2Fe031988c-0502-47ee-8c03-7d2bf82ac369%2Ffo7fgcn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 3 As a reminder, RN denotes the set of real sequences (uk)ken and
S :
RN
(uk)KEN
RN
(uk+1)KEN
i.e. S((uk)keN) is the sequence whose kth term is uk+1 (for example, S((uk)keN)o is u₁ or
S((uk)keN)1 is u2....) Let
4:
RN
RN
(uk) kEN S((uk)kEN)-3(uk) KEN
→
i.e. ((uk)keN) is the sequence whose kth term is uk+1-3uk
(1) Show that is a linear map.
(2) Let (ak)k be the sequence, ak
=
3k for any kN. Show that (ak)k is in Ker().
(3) Let (uk)ken be in Ker(). Show that uk = 3kuo.
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