Problem 3: Appearing to the right yet again is our familiar RLC series circuit. The voltage source, va, is a constant voltage and because of the capacitor in the loop the particular solution for i is zero. elle + Va C = i1-part = 0 (Kiedit + K2e2t, Kjeait + K2teait, if a1 = a2. if a1 + a2; R i1-c -comp i1(t) = i1-comp(t) + i1-part (t) where R ai = - 2L R 1 R R 1 and a2 2L LC 2L 2L LC The initial conditions for this circuit are vc(0¯) = 2va and iL(0~) = R: Provide a sketch for your expectations of i1 given these initial conditions and assuming that the circuit is underdamped. Solve for K1 and K2 given these initial conditions and for the case a1 # a2. K1 and K2 in terms of a1, a2, R, L, C, Va. Be sure to show

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+ VL -
Problem 3: Appearing to the right yet again is our
familiar RLOC series circuit. The voltage source, va,
a constant voltage and because of the capacitor in the
loop the particular solution for i is zero.
is
L
+
Va
Vc
i
1-part
K1eªit + K2eª2t,
if a1 + a2;
R
11-comp
Kjeªit + K2teª1t, if a1 = a2.
i1(t) = i1-comp(t) + i1-part (t)
where
2
R
R
+
2L
1
R
R
1
a1
and
a2
2L
LC
2L
2L
LC
The initial conditions for this circuit are vc(0-) = 2va and iL(0-)
Va
3R
%3D
Provide a sketch for your expectations of i1 given these initial conditions and assuming that the
circuit is underdamped.
Solve for K1 and K2 given these initial conditions and for the case a1 a2.
K1 and K2 in terms of a1, a2, R, L, C, va.
Be sure to show
+
Transcribed Image Text:+ VL - Problem 3: Appearing to the right yet again is our familiar RLOC series circuit. The voltage source, va, a constant voltage and because of the capacitor in the loop the particular solution for i is zero. is L + Va Vc i 1-part K1eªit + K2eª2t, if a1 + a2; R 11-comp Kjeªit + K2teª1t, if a1 = a2. i1(t) = i1-comp(t) + i1-part (t) where 2 R R + 2L 1 R R 1 a1 and a2 2L LC 2L 2L LC The initial conditions for this circuit are vc(0-) = 2va and iL(0-) Va 3R %3D Provide a sketch for your expectations of i1 given these initial conditions and assuming that the circuit is underdamped. Solve for K1 and K2 given these initial conditions and for the case a1 a2. K1 and K2 in terms of a1, a2, R, L, C, va. Be sure to show +
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