Problem 3: A q₁ = -10.0 nC point charge and a q2 = +20.0 nC point charge are 15 cm apart on the x-axis. 1. What is the electric potential at the point on the x-axis where the electric field is zero? 2. What is the electric field at the point on the x-axis, between the charges, where the electric potential is zero? a) In the figure below, where could a point with E = 0 be located (to the left, to the right, or between the charges)? If the distance between this point and q₁ is r, what should its distance from ¹92 be? (use 1921/1911: = 2 and the fact that electric field strength is proportional to q/r2) Mark the point E = 0 in the figure and compute its coordinate.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question

can you help me with Part D, thank you so much

**Problem 3:**

**Given:**

- \( q_1 = -10.0 \, \text{nC} \) (negative charge at \( x = 0 \))
- \( q_2 = +20.0 \, \text{nC} \) (positive charge at \( x = L = 15 \, \text{cm} \))

These point charges are placed 15 cm apart on the x-axis.

**Questions:**

1. Determine the electric potential at the point on the x-axis where the electric field is zero.
2. Identify the electric field at the point on the x-axis, between the charges, where the electric potential is zero.

**a) Finding \(\vec{E} = 0\):**

- Consider where a point with \(\vec{E} = 0\) could be located.
- Discuss if the point is to the left, right, or in between the charges.
- If the distance between this point and \( q_1 \) is \( r \), what should its distance from \( q_2 \) be?
- Use \(|q_2| / |q_1| = 2\) and the fact that electric field strength is proportional to \( q / r^2 \).
- Mark the point \(\vec{E} = 0\) and compute its coordinate.

**Diagram:**

The diagram shows a horizontal line representing the x-axis. Two charges are placed on this axis: 

- \( q_1 = -10 \, \text{nC} \) at \( x = 0 \)
- \( q_2 = +20 \, \text{nC} \) at \( x = L = 15 \, \text{cm} \)

**b) Electric Potential at \(\vec{E} = 0\):**

- Compute the electric potential at the point \(\vec{E} = 0\) as the sum of potentials from \( q_1 \) and \( q_2 \).

**c) Marking \( V = 0 \):**

- Identify the point between the charges where the electric potential is zero (\( V = 0 \)).
- Use \(|q_2| / |q_1| = 2\) and the fact that electric potential is proportional to \( q / r \) for a simple
Transcribed Image Text:**Problem 3:** **Given:** - \( q_1 = -10.0 \, \text{nC} \) (negative charge at \( x = 0 \)) - \( q_2 = +20.0 \, \text{nC} \) (positive charge at \( x = L = 15 \, \text{cm} \)) These point charges are placed 15 cm apart on the x-axis. **Questions:** 1. Determine the electric potential at the point on the x-axis where the electric field is zero. 2. Identify the electric field at the point on the x-axis, between the charges, where the electric potential is zero. **a) Finding \(\vec{E} = 0\):** - Consider where a point with \(\vec{E} = 0\) could be located. - Discuss if the point is to the left, right, or in between the charges. - If the distance between this point and \( q_1 \) is \( r \), what should its distance from \( q_2 \) be? - Use \(|q_2| / |q_1| = 2\) and the fact that electric field strength is proportional to \( q / r^2 \). - Mark the point \(\vec{E} = 0\) and compute its coordinate. **Diagram:** The diagram shows a horizontal line representing the x-axis. Two charges are placed on this axis: - \( q_1 = -10 \, \text{nC} \) at \( x = 0 \) - \( q_2 = +20 \, \text{nC} \) at \( x = L = 15 \, \text{cm} \) **b) Electric Potential at \(\vec{E} = 0\):** - Compute the electric potential at the point \(\vec{E} = 0\) as the sum of potentials from \( q_1 \) and \( q_2 \). **c) Marking \( V = 0 \):** - Identify the point between the charges where the electric potential is zero (\( V = 0 \)). - Use \(|q_2| / |q_1| = 2\) and the fact that electric potential is proportional to \( q / r \) for a simple
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON