Problem 26 Consider the following C++ program. void a(int &x, int y) { x = y; y = x + 1; } int b(int &x, int y) { y = x + 1; x = y; return y; } void c(int x[], int y) { if (y1) return; cout << x[y- 1] - y; c(x, y - 1); } int main() { } 3 (a) What is the ouput at line (a)? Answer: 22 (b) What is the ouput at line (b)? Answer: int x [6] = {1, 2, 3, 4, 5, 6}; int y [3] = {5, 4, 3}; cout << y[x [1]] % x[y[1]] << endl; a(x [0], x[1]); 4 cout << x[0] << x[1] << endl; cout <
Problem 26 Consider the following C++ program. void a(int &x, int y) { x = y; y = x + 1; } int b(int &x, int y) { y = x + 1; x = y; return y; } void c(int x[], int y) { if (y1) return; cout << x[y- 1] - y; c(x, y - 1); } int main() { } 3 (a) What is the ouput at line (a)? Answer: 22 (b) What is the ouput at line (b)? Answer: int x [6] = {1, 2, 3, 4, 5, 6}; int y [3] = {5, 4, 3}; cout << y[x [1]] % x[y[1]] << endl; a(x [0], x[1]); 4 cout << x[0] << x[1] << endl; cout <
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Please explain the answers and how they were gotten step by step. The
![### Problem 26
Consider the following C++ program.
```cpp
void a(int &x, int y) {
x = y;
y = x + 1;
}
int b(int &x, int y) {
y = x + 1;
x = y;
return y;
}
void c(int x[], int y) {
if (y < 1) return;
cout << x[y - 1] - y;
c(x, y - 1);
}
int main() {
int x[6] = {1, 2, 3, 4, 5, 6};
int y[3] = {5, 4, 3};
cout << y[x[1]] << x[y[1]] << endl; // line (a)
a(x[0], x[1]);
cout << x[0] << x[1] << endl; // line (b)
cout << b(2), x[3] << endl; // line (c)
cout << x[2] << x[3] << endl; // line (d)
c(y, 3); cout << endl; // line (e)
}
```
#### (a) What is the output at line (a)?
**Answer:**
3
#### (b) What is the output at line (b)?
**Answer:**
22
#### (c) What is the output at line (c)?
**Answer:**
4
#### (d) What is the output at line (d)?
**Answer:**
44
#### (e) What is the output at line (e)?
**Answer:**
024
### Explanation:
- **Line (a)**: `cout << y[x[1]] << x[y[1]] << endl;`
- `x[1]` is 2, so `y[x[1]]` is `y[2]` which is 3.
- `y[1]` is 4, so `x[y[1]]` is `x[4]` which is 5.
- Therefore the output is `3`.
- **Line (b)**: `a(x[0], x[1]);`
- `x[0]` becomes equal to `x[1]` which](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38650a9c-63f5-423f-8b89-b03c0dad949f%2F8b8bdcd2-ff90-4bf8-8033-6bf7ede276a5%2F3tjsfdh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem 26
Consider the following C++ program.
```cpp
void a(int &x, int y) {
x = y;
y = x + 1;
}
int b(int &x, int y) {
y = x + 1;
x = y;
return y;
}
void c(int x[], int y) {
if (y < 1) return;
cout << x[y - 1] - y;
c(x, y - 1);
}
int main() {
int x[6] = {1, 2, 3, 4, 5, 6};
int y[3] = {5, 4, 3};
cout << y[x[1]] << x[y[1]] << endl; // line (a)
a(x[0], x[1]);
cout << x[0] << x[1] << endl; // line (b)
cout << b(2), x[3] << endl; // line (c)
cout << x[2] << x[3] << endl; // line (d)
c(y, 3); cout << endl; // line (e)
}
```
#### (a) What is the output at line (a)?
**Answer:**
3
#### (b) What is the output at line (b)?
**Answer:**
22
#### (c) What is the output at line (c)?
**Answer:**
4
#### (d) What is the output at line (d)?
**Answer:**
44
#### (e) What is the output at line (e)?
**Answer:**
024
### Explanation:
- **Line (a)**: `cout << y[x[1]] << x[y[1]] << endl;`
- `x[1]` is 2, so `y[x[1]]` is `y[2]` which is 3.
- `y[1]` is 4, so `x[y[1]]` is `x[4]` which is 5.
- Therefore the output is `3`.
- **Line (b)**: `a(x[0], x[1]);`
- `x[0]` becomes equal to `x[1]` which
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