Problem 21.1 The lunar module is designed to make a safe landing on the moon if its vertical velocity at impact is Vmax ≤ 5 m/s. The acceleration of gravity on the moon is 1/6 the value on earth, gmoon = gearth/6. (a) Using the work-energy principle (conservation of energy), determine the maximum height h above the surface of the moon at which the pilot can safely shut off the engine when the velocity of the lunar module relative to the moon's surface is (i) (ii) (iii) zero; 3 m/s up; and 3 m/s down. (b) Repeat Part (a) only this time use the conservation of linear momentum. Is one approach easier than the other?

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Problem 21.1
The lunar module is designed to make a safe landing on the moon if its vertical velocity at impact is Vmax ≤
5 m/s. The acceleration of gravity on the moon is 1/6 the value on earth, gmoon = gearth/6.
(a) Using the work-energy principle (conservation of energy), determine the maximum height h above the
surface of the moon at which the pilot can safely shut off the engine when the velocity of the lunar
module relative to the moon's surface is
(i)
(ii)
(iii)
zero;
3 m/s up; and
3 m/s down.
(b) Repeat Part (a) only this time use the conservation of linear momentum. Is one approach easier than
the other?
Partial Ans: a (i) 7.0 m <h<8.0 m; (ii) 3 m<h <5 m; (iii) 3 m<h <5m
Transcribed Image Text:Problem 21.1 The lunar module is designed to make a safe landing on the moon if its vertical velocity at impact is Vmax ≤ 5 m/s. The acceleration of gravity on the moon is 1/6 the value on earth, gmoon = gearth/6. (a) Using the work-energy principle (conservation of energy), determine the maximum height h above the surface of the moon at which the pilot can safely shut off the engine when the velocity of the lunar module relative to the moon's surface is (i) (ii) (iii) zero; 3 m/s up; and 3 m/s down. (b) Repeat Part (a) only this time use the conservation of linear momentum. Is one approach easier than the other? Partial Ans: a (i) 7.0 m <h<8.0 m; (ii) 3 m<h <5 m; (iii) 3 m<h <5m
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