Problem 2.48 An inverted hemispherical bowl of radius R carries a uniform surface charge density o. Find the potential difference between the "north pole" and the center. [Answer: (Ra/2eo)(√2-1)1

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Q: R1= 5A I tot =. Rtot =. AV1= I1=- R2= Rg= 12n AV2 =. I2=- 24V AV3=. I3=. AV4= 14=- R4 = 8n

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