PROBLEM 2.2 A 1.5 m long steel wire of 6 mm diameter steel wire is subjected to a 3.4 kN tensile load. Knowing that E = 200 GPa, determine (a) the elongation of the wire, and (b) the corresponding normal stress. [Ans. (a) 0.902 mm (b) 120.3 MPa] |3D
PROBLEM 2.2 A 1.5 m long steel wire of 6 mm diameter steel wire is subjected to a 3.4 kN tensile load. Knowing that E = 200 GPa, determine (a) the elongation of the wire, and (b) the corresponding normal stress. [Ans. (a) 0.902 mm (b) 120.3 MPa] |3D
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
2.2 B please
![Iding normal stress caused by the load.
[Ans. (a) 9.96 mm (b) 109.1 MPa]
PROBLEM 2.2
A 1.5 m long steel wire of 6 mm diameter steel wire is subjected to
a 3.4 kN tensile load. Knowing that E = 200 GPa, determine (a) the
elongation of the wire, and (b) the corresponding normal stress.
[Ans. (a) 0.902 mm (b) 120.3 MPa]
PROBLEM 2.15
A solid cylindrical steel rod is made from three portions as
shown in Fig Q5b. It is subjected to a tensile axial load P.
Knowing that the modulus of elasticity, E = 200 GPa,
determine (a) the value of the load P so that the total
deformation is 0.05 mm, and (b) the deformation of the central
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7c9c3259-16b0-44c2-9416-39962bcc9c3e%2F6cd93528-f172-40a6-a1a8-5883e6ec13f0%2Fh4h94ml_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Iding normal stress caused by the load.
[Ans. (a) 9.96 mm (b) 109.1 MPa]
PROBLEM 2.2
A 1.5 m long steel wire of 6 mm diameter steel wire is subjected to
a 3.4 kN tensile load. Knowing that E = 200 GPa, determine (a) the
elongation of the wire, and (b) the corresponding normal stress.
[Ans. (a) 0.902 mm (b) 120.3 MPa]
PROBLEM 2.15
A solid cylindrical steel rod is made from three portions as
shown in Fig Q5b. It is subjected to a tensile axial load P.
Knowing that the modulus of elasticity, E = 200 GPa,
determine (a) the value of the load P so that the total
deformation is 0.05 mm, and (b) the deformation of the central
%3D
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