Problem 2. The common tangent BC of a reverse curve is 280.5 m and has a bearing of S 47°31' E. AB is the tangent of the first curve whose bearing is N72°45' E. CD is the tangent of the second curve whose bearing is N38°13′E. A is at the PC while D is at the PT. The radius of the first curve is 180m and its PI is at station 12+523.37. Find the stationing of PT.
Problem 2. The common tangent BC of a reverse curve is 280.5 m and has a bearing of S 47°31' E. AB is the tangent of the first curve whose bearing is N72°45' E. CD is the tangent of the second curve whose bearing is N38°13′E. A is at the PC while D is at the PT. The radius of the first curve is 180m and its PI is at station 12+523.37. Find the stationing of PT.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Problem 2. The common tangent BC of a reverse curve is 280.5 m and has a bearing of S 47°31'
E. AB is the tangent of the first curve whose bearing is N72°45' E. CD is the tangent of the second
curve whose bearing is N38°13′E. A is at the PC while D is at the PT. The radius of the first curve
is 180m and its PI is at station 12+523.37. Find the stationing of PT.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90aa1e97-138e-4ba5-bdb5-81a51b33b3ab%2Fc1761997-c819-483e-993f-0e76efc5aba3%2Fhdlmrb_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 2. The common tangent BC of a reverse curve is 280.5 m and has a bearing of S 47°31'
E. AB is the tangent of the first curve whose bearing is N72°45' E. CD is the tangent of the second
curve whose bearing is N38°13′E. A is at the PC while D is at the PT. The radius of the first curve
is 180m and its PI is at station 12+523.37. Find the stationing of PT.
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