Problem 2. (i.e.+¹=1). Let p be a real number such that 1

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part3 d measure and operator theory ( using previous part as result)
Problem 2.
(i.e.+¹=1).
Pq
hat do you
Let p be a real number such that 1 < p <∞ and let q be its conjugate
1. Let f LP(R). Consider the operator T defined by
(Tf)(x) = f(1) di
Show that the operator T is well defined for all a > 0, and the function Tf is.
continuous on 10,00[ and satisfies
|(Tf)(x)| ≤x|f||p>
2. If f,g LP(R), then
|(Tf)(x) - (Tg)(x)| < xƒ-9|p₁\x>0.
3. Let g be a continuous function with compact support in 10,00[. Set G(x) =
fog(t)dt.
(a) Show that G is of class C¹ (R) and that 0≤G(z) <|9||
(b) Deduce that lim (G(x)) = 0 and that (G(x)) dx < +∞o.
(c) Show that
∞0++-3
SzG'(x) (G(x))³-¹ dx + + [** (G(x)) dx =
: - * \9 (2)| (G(x)) ³-¹ dr.
(d) Deduce that
p-1
P=¹ (G(x)) dx = - * \9(2)| (G(x))"~¹ dx.
(e) Use Hölder inequality to deduce that
||G||<₁||||, and ||7g||p²|||||p
4. Recall that the space of continuous function with compact support is dense in
LP(R). Use the previous parts and apply Fatou's lemma to deduce the Hardy
inequality:
||TS||||||
Transcribed Image Text:Problem 2. (i.e.+¹=1). Pq hat do you Let p be a real number such that 1 < p <∞ and let q be its conjugate 1. Let f LP(R). Consider the operator T defined by (Tf)(x) = f(1) di Show that the operator T is well defined for all a > 0, and the function Tf is. continuous on 10,00[ and satisfies |(Tf)(x)| ≤x|f||p> 2. If f,g LP(R), then |(Tf)(x) - (Tg)(x)| < xƒ-9|p₁\x>0. 3. Let g be a continuous function with compact support in 10,00[. Set G(x) = fog(t)dt. (a) Show that G is of class C¹ (R) and that 0≤G(z) <|9|| (b) Deduce that lim (G(x)) = 0 and that (G(x)) dx < +∞o. (c) Show that ∞0++-3 SzG'(x) (G(x))³-¹ dx + + [** (G(x)) dx = : - * \9 (2)| (G(x)) ³-¹ dr. (d) Deduce that p-1 P=¹ (G(x)) dx = - * \9(2)| (G(x))"~¹ dx. (e) Use Hölder inequality to deduce that ||G||<₁||||, and ||7g||p²|||||p 4. Recall that the space of continuous function with compact support is dense in LP(R). Use the previous parts and apply Fatou's lemma to deduce the Hardy inequality: ||TS||||||
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