Problem 2. For this problem, you may use the following general result: pn – 1 1+r+r² + r3 | + ... + rn-1 г - 1 (a) Let r = -x². Apply the formula above, along with some algebra, to show 1 = 1- x? + x* – a6 + ...+ (-1)"-lx²n-2 + (-1)";?n 1+x? 1+x² (b) Integrate the above formula over [0, 1] to show (-1)n+1 2n – 1 x2n dx 1 1 1 1 + (-1)" - 7 1+x² (c) Use the Integral Comparison Theorem to show that x2n 1 dx < 1+ x² 2n + 1 (Hint: The integrand is < x²n.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Problem 2. For this problem, you may use the following general result:
1
1+r+ r² + r³3 + ·
п-1
+r
1
(a) Let r = -x². Apply the formula above, along with some algebra, to show
(-1)"x²n
1+ x2
1
1– x2 + x* .
x6 +
+ (-1)"-1x2n-2 +
1+ x²
(b) Integrate the above formula over [0, 1] to show
1
1
(-1)n+1
x2n dx
1
1
(-1)" /
2n – 1
1+ x2
(c) Use the Integral Comparison Theorem to show that
x2n
1
dx <
1+ x2
2n + 1
(Hint: The integrand is < a2n.)
(d) Prove the Gregory-Leibniz Formula:
1 1
(-1)n-1
1
1
4
5
2n – 1
7
9
n=1
(Hint: Use (b) and (c) to show the partial sums S, satisfy Sn
and - Sn <
Then conclude
4
2n+1
2n+1
that |Sn - |< 2n+1» and prove the series converges to 7.)
Transcribed Image Text:Problem 2. For this problem, you may use the following general result: 1 1+r+ r² + r³3 + · п-1 +r 1 (a) Let r = -x². Apply the formula above, along with some algebra, to show (-1)"x²n 1+ x2 1 1– x2 + x* . x6 + + (-1)"-1x2n-2 + 1+ x² (b) Integrate the above formula over [0, 1] to show 1 1 (-1)n+1 x2n dx 1 1 (-1)" / 2n – 1 1+ x2 (c) Use the Integral Comparison Theorem to show that x2n 1 dx < 1+ x2 2n + 1 (Hint: The integrand is < a2n.) (d) Prove the Gregory-Leibniz Formula: 1 1 (-1)n-1 1 1 4 5 2n – 1 7 9 n=1 (Hint: Use (b) and (c) to show the partial sums S, satisfy Sn and - Sn < Then conclude 4 2n+1 2n+1 that |Sn - |< 2n+1» and prove the series converges to 7.)
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The result 1+r+r2+r3++rn-1=rn-1r-1.

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