Problem 2. Define a function h(x) on (-∞, +∞) by the following rule, sin (1/x), x 0. x = 0 h(x) = { 0, Compute the limit as x approaches 0 of k(x) = xh(x). Explain why it is invalid to simply compute the limit as k(0) = 0.h(0)=0.0=0?
Problem 2. Define a function h(x) on (-∞, +∞) by the following rule, sin (1/x), x 0. x = 0 h(x) = { 0, Compute the limit as x approaches 0 of k(x) = xh(x). Explain why it is invalid to simply compute the limit as k(0) = 0.h(0)=0.0=0?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
problem 2 plz
![Problem 1. The following function has domain (-1,0) U (0, ∞0),
−1+√1+x
Xx
f(x) =
Make a table of values of f(x) for x = ±1, 0.1, 0.01, and ±0.001. Use your
table to guess a limiting value for f(x) as x → 0. Finally, use difference-
of-squares rationalization to find a continuous function g(x) whose domain
contains (-1, ∞) such that f(x) equals g(x) on (-1,0) U (0, ∞o). Use this to
prove that your guess is correct.
Problem 2. Define a function h(x) on (-∞, +∞) by the following rule,
sin (1/x), x 0.
x = 0
h(x) =X{ 0,
Compute the limit as x approaches 0 of k(x) = xh(x). Explain why it is
invalid to simply compute the limit as k(0) = 0.h(0)=0.0=0?
81
YOUKY](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05136949-0414-47eb-a73e-74f55563dd77%2F74f97964-05de-4e25-b5fa-7af7f5c0a040%2Fiz72sf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 1. The following function has domain (-1,0) U (0, ∞0),
−1+√1+x
Xx
f(x) =
Make a table of values of f(x) for x = ±1, 0.1, 0.01, and ±0.001. Use your
table to guess a limiting value for f(x) as x → 0. Finally, use difference-
of-squares rationalization to find a continuous function g(x) whose domain
contains (-1, ∞) such that f(x) equals g(x) on (-1,0) U (0, ∞o). Use this to
prove that your guess is correct.
Problem 2. Define a function h(x) on (-∞, +∞) by the following rule,
sin (1/x), x 0.
x = 0
h(x) =X{ 0,
Compute the limit as x approaches 0 of k(x) = xh(x). Explain why it is
invalid to simply compute the limit as k(0) = 0.h(0)=0.0=0?
81
YOUKY
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