Problem 2. A block R of rubber with dimensions a x a x L is confined between the plane parallel walls of a square hole in a steel block, S. A uniformly distributed pressure po is applied to the top of the rubber block by a force F. a a S Derive a formula for the lateral pressure p between a) the rubber and the steel. (Ignore friction between the rubber and the steel, and assume the steel block is rigid in comparison with the rubber.) F b) Derive a formula for the dilatation e of the rubber. c) Derive a formula for the strain energy density u of the rubber. R S ka
Problem 2. A block R of rubber with dimensions a x a x L is confined between the plane parallel walls of a square hole in a steel block, S. A uniformly distributed pressure po is applied to the top of the rubber block by a force F. a a S Derive a formula for the lateral pressure p between a) the rubber and the steel. (Ignore friction between the rubber and the steel, and assume the steel block is rigid in comparison with the rubber.) F b) Derive a formula for the dilatation e of the rubber. c) Derive a formula for the strain energy density u of the rubber. R S ka
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:F
Problem 2. A block R of rubber with dimensions a x
a xL is confined between the plane parallel walls of a
square hole in a steel block, S. Auniformly distributed
pressure po is applied to the top of the rubber block by a
force F.
a
S
Derive a formula for the lateral pressure p between
a)
the rubber and the steel. (Ignore friction between
the rubber and the steel, and assume the steel block
d:
is rigid in comparison with the rubber.)
F
b)
Derive a formula for the dilatation e of the rubber.
Derive a formula for the strain energy density u of
c)
the rubber.
R
L.
S
ka>
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