Problem # 2 Using the principle of superposition and the table provided and given that that the beam's modulus of elasticity is E=200 GPa and its moment of inertia is /= 100x106 mm². • Find the reactions and the fixed end moment for the beam shown • Determine the internal moment at section E 50 kN Wo= 120 kN/m D 3 m Beam A P Umax -Omax max E 6 m Slope Omax = -PL² 2E1 -WOL³ 24EI B + Deflection Umax -PL³ 3EI -WOL 30EI 2m +1m| Elastic Curve -Px² (3L - x) 6EI (10L³ - 10L²x + 5Lx²-x v= -wor² 120EIL

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Problem # 2
Using the principle of superposition and the table provided and given that that the beam's
modulus of elasticity is E=20O GPa and its moment of inertia is l= 100x106 mm4.
Find the reactions and the fixed end moment for the beam shown
Determine the internal moment at section E
50 kN
wo = 120 kN/m
В
D
A
3 т
6 m
2 т
+ 1m
Beam
Slope
Deflection
Elastic Curve
'max
-PL?
Omax =
2EI
- Pr?
(3L – x)
6EI
-PL
Vmax =
v =
3EI
mat
Wo
Umax
-woL
-wox?
(10L³ – 10L²X + 5Lx² – x³)
0mar =
Umax =
v =
24EI
30EI
120EIL
Omax
Transcribed Image Text:Problem # 2 Using the principle of superposition and the table provided and given that that the beam's modulus of elasticity is E=20O GPa and its moment of inertia is l= 100x106 mm4. Find the reactions and the fixed end moment for the beam shown Determine the internal moment at section E 50 kN wo = 120 kN/m В D A 3 т 6 m 2 т + 1m Beam Slope Deflection Elastic Curve 'max -PL? Omax = 2EI - Pr? (3L – x) 6EI -PL Vmax = v = 3EI mat Wo Umax -woL -wox? (10L³ – 10L²X + 5Lx² – x³) 0mar = Umax = v = 24EI 30EI 120EIL Omax
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