Problem 2: Three capacitors are connected in series as shown in the figure. The capacitances are C,= 5.3 µF, and C2 = 5.2 uF, C3 is unknown, and the charge stored in each capacitor is Q = 10.5 µC. Part (a) Express the capacitance C of a capacitor in terms of charge Q and voltage AV on it. C= QAV / Correct! Part (b) Apply the above formula to capacitor C, to find an expression for the potential difference AV12 across it. AV12 = Q'C1 / Correct! Part (c) Express the potential difference AV12 through potentials V; and V, where V and V2 are the potentials measured in the wires 1 and 2, respectively, relative to the negative side of the battery. AV12 = V1 - V2 Correct! Part (d) Calculate V2 in V given V =9 V. V2 = Part (e) Repeat the above procedure for capacitor C2 and calculate the potential at point 3, V3 in V. V3 =

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Chapter1: Units, Trigonometry. And Vectors
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Problem 2: Three capacitors are connected in series as shown in the figure. The
capacitances are C; = 5.3 µF, and C2= 5.2 µF, C3 is unknown, and the charge stored in each capacitor
is Q = 10.5 µC.
Part (a) Express the capacitance C of a capacitor in terms of charge Q and voltage AV on it.
C= Q/AV
/ Correct!
Part (b) Apply the above formula to capacitor C, to find an expression for the potential difference AV2 across it.
AV12 = Q/C1
/ Correct!
Part (c) Express the potential difference AV12 through potentials V; and V2 where V; and V2 are the potentials measured in the wires 1 and 2,
respectively, relative to the negative side of the battery.
AV12 = V1 - V2 v Correct!
Part (d) Calculate V2 in V given V1 =9 V.
V2 =
Part (e) Repeat the above procedure for capacitor C, and calculate the potential at point 3, V3 in V.
V3=
Transcribed Image Text:Problem 2: Three capacitors are connected in series as shown in the figure. The capacitances are C; = 5.3 µF, and C2= 5.2 µF, C3 is unknown, and the charge stored in each capacitor is Q = 10.5 µC. Part (a) Express the capacitance C of a capacitor in terms of charge Q and voltage AV on it. C= Q/AV / Correct! Part (b) Apply the above formula to capacitor C, to find an expression for the potential difference AV2 across it. AV12 = Q/C1 / Correct! Part (c) Express the potential difference AV12 through potentials V; and V2 where V; and V2 are the potentials measured in the wires 1 and 2, respectively, relative to the negative side of the battery. AV12 = V1 - V2 v Correct! Part (d) Calculate V2 in V given V1 =9 V. V2 = Part (e) Repeat the above procedure for capacitor C, and calculate the potential at point 3, V3 in V. V3=
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