Problem 2: Three candidates for deanship in a college were voted on by 75 faculty members. The result is shown below. Test whether the candidates are equally preferred. Use 0.01 and 0.05 level. Candidate Y Observed 13 34 28 Expected 15 25 25

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6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Question

Test of goodness of fit.

Answer the first picture just like how the second picture is answered

Example 1
After 100 tosses of a coin, 44 came out heads and 56 tails. As expected, based on theory, they should come out 50/50.
Heads
Tails
Observed (O)
44
56
Expected (E)
50
50
(44 – 50) (56– 50)
Ho: The coin is not biased.
Ha: The coin is biased.
.(0- E}
x² ==
50
50
%3D
E
(-6) (6)
df = (I – 1)(J – 1)
50
50
1.44 <
3.84
Ассept
The coin is not biased.
36 36
Re
На.
(I-1)(J-1)
0.05
+
%3D
50 50
x´(2-1)(2–1)
0.05
72
0.05 -x
= 3.84
50
x? =1.44
Example 2
90 qualified high school graduates are asked which of three universities they prefer. The result is shown below.
School X
School Y
School Z
Observed (O)
18
38
34
Expected (E)
30
30
30
(18–30) (38– 30) (34– 30)
.(0 - E)} x²
x² =E
Ho: There is no significant difference in the
preference of the students in the three
universities.
+
30
30
30
E
(-12) (8) (4)°
Ha: Ho: There is no significant difference
in the preference of the students in the
df = (I – 1)(J – 1)
30
30
30
three universities.
144 64 16
0.05
(1-1)(J-1)
+
30 30
%3D
30
7.47 >
5.99
0.05 X (2–1)(3–1)
224
Accept Ha, Reject Ho.
There is a significant difference in the preference of the
30
0.05 X2 = 5.99
x' = 7.47
students in the three universities.
LIDESMANIA.C
LIDESMANIA.C
Transcribed Image Text:Example 1 After 100 tosses of a coin, 44 came out heads and 56 tails. As expected, based on theory, they should come out 50/50. Heads Tails Observed (O) 44 56 Expected (E) 50 50 (44 – 50) (56– 50) Ho: The coin is not biased. Ha: The coin is biased. .(0- E} x² == 50 50 %3D E (-6) (6) df = (I – 1)(J – 1) 50 50 1.44 < 3.84 Ассept The coin is not biased. 36 36 Re На. (I-1)(J-1) 0.05 + %3D 50 50 x´(2-1)(2–1) 0.05 72 0.05 -x = 3.84 50 x? =1.44 Example 2 90 qualified high school graduates are asked which of three universities they prefer. The result is shown below. School X School Y School Z Observed (O) 18 38 34 Expected (E) 30 30 30 (18–30) (38– 30) (34– 30) .(0 - E)} x² x² =E Ho: There is no significant difference in the preference of the students in the three universities. + 30 30 30 E (-12) (8) (4)° Ha: Ho: There is no significant difference in the preference of the students in the df = (I – 1)(J – 1) 30 30 30 three universities. 144 64 16 0.05 (1-1)(J-1) + 30 30 %3D 30 7.47 > 5.99 0.05 X (2–1)(3–1) 224 Accept Ha, Reject Ho. There is a significant difference in the preference of the 30 0.05 X2 = 5.99 x' = 7.47 students in the three universities. LIDESMANIA.C LIDESMANIA.C
Problem 1: A die is rolled 60 times. The spots 1 to 6 are recorded below. Test the
biasness of the die using 0.01 and 0.05 level.
Spot
1
2
Observed
12
8
15
14
Expected
10
10
10
10
10
10
Problem 2: Three candidates for deanship in a college were voted on by 75 faculty
members. The result is shown below. Test whether the candidates are equally
preferred. Use 0.01 and 0.05 level.
Candidate
Y
Observed
13
34
28
Expected
15
25
25
LIDESMANIA.C
Transcribed Image Text:Problem 1: A die is rolled 60 times. The spots 1 to 6 are recorded below. Test the biasness of the die using 0.01 and 0.05 level. Spot 1 2 Observed 12 8 15 14 Expected 10 10 10 10 10 10 Problem 2: Three candidates for deanship in a college were voted on by 75 faculty members. The result is shown below. Test whether the candidates are equally preferred. Use 0.01 and 0.05 level. Candidate Y Observed 13 34 28 Expected 15 25 25 LIDESMANIA.C
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