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Problem 2 The steel plate is 0.3m thick and has a density of 7850 kg/m³. Given that the center of mass for a uniform thickness plate is at the centroid. Find the location of the center of mass of the plate. The use static equilibrium equations to solve for the reactions at the pin and roller support. Note the units on the constant in the function y² = 2 ·x is 2 meters. Cintaguation aud metk

Problem 2 The steel plate is 0.3m thick and has a density of 7850 kg/m³. Given that the center of mass for a uniform thickness plate is at the centroid. Find the location of the center of mass of the plate. The use static equilibrium equations to solve for the reactions at the pin and roller support. Note the units on the constant in the function y² = 2 ·x is 2 meters. Cintaguation aud metk

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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PART2: Then use static equilibrium equations to solve for the reactions at the pin and roller support. 

 

Solve for reactions at pin and roller support

Problem 2 The steel plate is 0.3m thick and has a density of 7850 kg/m³. Given that the center of mass for a uniform thickness plate is at the centroid. Find the location of the center of mass of the plate. The use static equilibrium equations to solve for the reactions at the pin and roller support. Note the units on the constant in the function y² = 2·x is 2 meters. You may use a combination of integration methods and methods for composite bodies. y? = 2x 2 m 2 m y = -x- B. 45° 2 m
Transcribed Image Text:Problem 2 The steel plate is 0.3m thick and has a density of 7850 kg/m³. Given that the center of mass for a uniform thickness plate is at the centroid. Find the location of the center of mass of the plate. The use static equilibrium equations to solve for the reactions at the pin and roller support. Note the units on the constant in the function y² = 2·x is 2 meters. You may use a combination of integration methods and methods for composite bodies. y? = 2x 2 m 2 m y = -x- B. 45° 2 m
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