Please help answer the question with elaborate step by step solution and explain how to solve it. Problem 2IR Spectrum(liquid film)298417411243400030002000160012008000.0V (cm1)100Mass Spectrum430.58060UV spectrum1.0solvent : ethanol15.4 mg / 10 mlspath length : 1.00 cm4029M+' = 88201.54080120160200240280200250300350m/e2 (nm)13C NMR Spectrum(50.0 MHz, CDCI, solution)solventproton decoupled2001601208040d (ppm)1H NMR Spectrum(200 MHz, CDCI, solution)TMS18 (ppm)108.6.54% of base peakLO Unknown Spectroscopy Practice Problems: Problem #2What hydrocarbon (hydrogen and carbon only) formula would you use to start thisproblem? How many degrees of unsaturation does it have?Looking at the IR, what characteristic bond is present?How would you revise your molecular formula and degrees of unsaturation based on theIR spectrum?

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Problem 2 IR Spectrum (liquid film) 2984 1741 1243 4000 3000 2000 1600 1200 800 0.0 V (cm) 100 Mass Spectrum 43 0.5 80 60 UV spectrum 1.0 solvent : ethanol 40 29 M+ = 88 15.4 mg / 10 mls path length : 1.00 cm 20 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e 1 (nm) 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled solvent 200 160 120 80 40 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) TMS 1 8 (ppm) 10 9. 8 7 4 2 LO CO % of base peak

Problem 2 IR Spectrum (liquid film) 2984 1741 1243 4000 3000 2000 1600 1200 800 0.0 V (cm) 100 Mass Spectrum 43 0.5 80 60 UV spectrum 1.0 solvent : ethanol 40 29 M+ = 88 15.4 mg / 10 mls path length : 1.00 cm 20 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e 1 (nm) 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled solvent 200 160 120 80 40 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) TMS 1 8 (ppm) 10 9. 8 7 4 2 LO CO % of base peak

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL1: Infrared Spectroscopy

Section: Chapter Questions

Problem 15CTQ

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