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Problem (2): Given f(x) = 2x+cos (2x), defined over x = {0, x/4, /2, 3/4, T}, use divided difference table to answer questions 1, 2, 3, and 4. 1). The value of the term f [xo,X1X₂] is: A) 2/ # B) 16/T D) 4/1 2) The number of cubic polynomials (n-3) that we can get from the given data: C) 3 A) 1 3) Starting from (x = π/4), P₂() is: B) -3 x 3 # B) 2 Al A C) 12/T 4) Starting from (x = x/2), the first derivative B)-2 D) 2 T dP, (x) dx C) 0 D) 4 D) 27 at (x= π/2) is: D) -4 E) None E) None E) None E) None

Problem (2): Given f(x) = 2x+cos (2x), defined over x = {0, x/4, /2, 3/4, T}, use divided difference table to answer questions 1, 2, 3, and 4. 1). The value of the term f [xo,X1X₂] is: A) 2/ # B) 16/T D) 4/1 2) The number of cubic polynomials (n-3) that we can get from the given data: C) 3 A) 1 3) Starting from (x = π/4), P₂() is: B) -3 x 3 # B) 2 Al A C) 12/T 4) Starting from (x = x/2), the first derivative B)-2 D) 2 T dP, (x) dx C) 0 D) 4 D) 27 at (x= π/2) is: D) -4 E) None E) None E) None E) None

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Problem (1): Given f(x) = 2x+cos(2x), defined over x = {0, π/4, /2, 3/4, π), use divided difference table to answer questions 1, 2, 3, and 4. 1). The value of the term f [xo,X1X₂] is: A) 2/ # B) 16/T A) 1 B) 2 3) Starting from (x=x/4), P₂(π) is: 2) The number of cubic polynomials (n=3) that we can get from the given data: 3 # B) -3 z A) 4 C) 12/T B) -2 C) 3 4) Starting from (x = x/2), the first derivative D) 27 dP{(x) dx D) 4/T C) 0 D) 4 D) 2# at (x=π/2) is: D) -4 E) None E) None E) None E) None the
Transcribed Image Text:Problem (1): Given f(x) = 2x+cos(2x), defined over x = {0, π/4, /2, 3/4, π), use divided difference table to answer questions 1, 2, 3, and 4. 1). The value of the term f [xo,X1X₂] is: A) 2/ # B) 16/T A) 1 B) 2 3) Starting from (x=x/4), P₂(π) is: 2) The number of cubic polynomials (n=3) that we can get from the given data: 3 # B) -3 z A) 4 C) 12/T B) -2 C) 3 4) Starting from (x = x/2), the first derivative D) 27 dP{(x) dx D) 4/T C) 0 D) 4 D) 2# at (x=π/2) is: D) -4 E) None E) None E) None E) None the
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