Problem 2 Given: 0.75 m 6 10,4 mi D Mass of car: 1400 kg m- 2 m .5 m- -2 m- 1.25 m Mass of trailer: 800 kg Braking force at C (µc= 0.40) is applied and causes skid. PIN G, 0.75 m 6 0.4 1 FREE TO ROLL -FREE TO ROLL m-- 2 m .5 m-- 2 m- 1.25 m Determine the reactions at B, C, and D.

Q: Beam AB is subjected to a uniform load of 240 N/m and is supported at B by a post BC as shown in…

A: Step 1

Q: 2) Body A weighs 700 Ib and body B weighs goo16. The coefficient of friction for all surfaces of…

A:

Q: Gear A has an angular acceleration of 2t³ rads/s2, where t is in seconds. The gear is initially…

A: αA=4t2dωdt=αA=2t2ω=∫2t2dtω=2t33+cat t=0   ω=15c=15so,ω=2t33+15

Q: 1) Which of the following gives the acceleration of the car. 2) Which of the following gives the…

A:

Q: 20 kN.m 2 kN/m A- 2m -4m -2m- Which of the following best describes the elastic curve (deformed…

A: Finding out deformed shape of the beam.

Q: 6. The two uniform sheets of plywood, each of length L and weight W, are propped as shown. If the…

A: To determine whether the two sheets of plywood will remain at rest, need to perform a static…

Q: 5. The car is given a leftward acceleration of 2.500 m/sec?. The sum of the friction forces FA and…

A: This question is solved with the help of the equilibrium equation.  Let's draw the free-body diagram…

Q: Uniform shaft is fixed at one end and free in other end, if (0,0) (1,0) a²0 = a?. dx² • 0 0 0(0,t) =…

A: Angular Displacement It is the angle made by the body while moving in a circular path. When a rigid…

Q: Compute the weight of the chassis, the weight of the

A: Given: axle loads (normal forces at A and B) = 41 900 N  rear axle load increases = 48 700 N

Q: The beam of negligible weight is supported horizontally by two springs. If the beam is horizontal…

A:

Q: Homework: A single lane simply supported concrete beam bridge with a span of L=10 m, the highway…

A: Given:- The length of the bridge span = L = 10 m  The grade of the highway = Grade III The density…

Q: Q6/A simply supported beam of rectangular section, support the load shown in Fig. Answer the…

A: Answer  Let us first calculate the Design Moment 'Mu' Design moment 'Mu' is Maximum Moment on beam…

Q: Support Reaction Ay unit Dirction(U/D) kN 10 kN-m By kN Support Reaction unit Ma Dirction(CW/CCW) 10…

A:

Q: Write the stiffness matrix for the one-story.

A:

Q: Calculate the stretch (elongation) in spring AC. -3 m- 4 m kAc = 20 N/m wwww ww kan = 30 N/m 3 m m=…

A:

Q: The rod AB has a velocity and an acceleration at the wheel A of 4 m/sec and 6 m/sec?. Given the…

A:

Q: The trailer has a mass of 400kg and the mass center at G. is being pulled by a horizontal force of…

A: Newton's second law of motion: Newton's second law of motion describes the motion of the body.…

Q: Q1, A square reinforced concrete slab of dimensions (a x a) m with fixed supported on all edges,…

A: A square slab having size a x a. Maximum poitive moment = 25 kN.m Maximum Negative moment = 40 kN.m…

Q: The 11-lb block has a velocity of 4.29 ft/s when the force of F = (257.6t2) Ib-ft/sec2 is applied.…

A:

Q: Solve the differential equation for dy/dx = 4/x^2-1

A: Differential Equations: The equations which relate one or more functions together making an equation…

Q: 3 kN/m 3 m в с 1 m

A:

Q: 1. Det.moment of inertia. Y 3" r= 3" 1" 2"

A:

Q: Q2: Determine (Y). D2 Y Q I/sec L (m) D1 D2 100 0.8 2.5 0.36 D2 Y D1 + Hg-

A: Given Q = 100 l/sec D2/D1 = 0.8 y/D2 = 2.5 and L = 0.36 m

Q: Compute the midspan value of El y for the beam loaded as shown. 300 N/m A B |.5m 05 2 m

A: Given data:

Q: POLレ Determine the reactions at B, C, and D.

A:

Q: Determine the reaction at A if w=40 kN/m, L=5 W C 2MB A 0000 RA -L/2- -L/2- BAB

A: Given Data: w=40 kn/m L=5m   It is asked to calculate Deflection at A using moment area method.

Q: Determine the maximum flexural stresses in the Tee Beam (Fig. 5) and the locations where it occurs.…

A:

Q: Detemine the plastic moment strength (kN-m) of a C15x50, A36 steel, about the minor axis. d= 381 mm…

A: section : c15×50  plastic moment of section (Mp)?

Q: For the shown loading system, determine: ) The resultant force (FR) 2) The intersection of the…

A:

Q: nowmobile has a weight of 260 lb, centered at G₁. the rider has a weight of 180 lb, centered at G₂.…

A: Mass of snowmobile=260lb Mass of rider =180lb h=2ft

Q: D. In the figure, the coefficient friction of Block A and B are 0.15 and 0.25 respectively. Block C…

A: We have to determine the value of tensions at Pulley connecting A and B, b and c, Force at A and B…

Q: Determine the reactions at B, c, and D. Note: Pin supports can resist both vertical and horizontal…

A:

Q: PROBLEM 2: A support block is acted upon by two forces as shown. Knowing that the coefficients of…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.