Problem 2: Formulating a loop invariant for the purpose of proving the correctness of an iterative algorithm can be a bit of a challenge. However, for the following algorithm, finding a loop invariant is not difficult. Here is the algorithm: SumArray (A[1..N]): sum = 0 i = 1 for (i < N): { sum = sum + A[i] i=i+ 1 } return sum (a) State a loop invariant the can be used to prove the correctness of this algorithm (correct calculation of the sum of all values in A[1..N]). (b) Show the prove using your invariant in three steps: initialization, maintenance, and termination.
Problem 2: Formulating a loop invariant for the purpose of proving the correctness of an iterative algorithm can be a bit of a challenge. However, for the following algorithm, finding a loop invariant is not difficult. Here is the algorithm: SumArray (A[1..N]): sum = 0 i = 1 for (i < N): { sum = sum + A[i] i=i+ 1 } return sum (a) State a loop invariant the can be used to prove the correctness of this algorithm (correct calculation of the sum of all values in A[1..N]). (b) Show the prove using your invariant in three steps: initialization, maintenance, and termination.
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![Problem 2: Formulating a loop invariant for the purpose of proving the correctness of an
iterative algorithm can be a bit of a challenge. However, for the following algorithm, finding a
loop invariant is not difficult. Here is the algorithm:
SumArray (A[1..N]):
sum = 0
i = 1
for (i < N) :
{
sum = sum + A[i]
i = i + 1
}
return sum
(a) State a loop invariant the can be used to prove the correctness of this algorithm (correct
calculation of the sum of all values in A[1..N]).
(b) Show the prove using your invariant in three steps: initialization, maintenance, and
termination.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffbb9a233-ccbf-4977-a45b-ea6968028606%2F73602d1f-5ff6-4fcf-8758-4251bc49638d%2Fsfoa0a6_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 2: Formulating a loop invariant for the purpose of proving the correctness of an
iterative algorithm can be a bit of a challenge. However, for the following algorithm, finding a
loop invariant is not difficult. Here is the algorithm:
SumArray (A[1..N]):
sum = 0
i = 1
for (i < N) :
{
sum = sum + A[i]
i = i + 1
}
return sum
(a) State a loop invariant the can be used to prove the correctness of this algorithm (correct
calculation of the sum of all values in A[1..N]).
(b) Show the prove using your invariant in three steps: initialization, maintenance, and
termination.
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