Problem 2 Design of Shear Members A cantilever beam has a span of 3 m. The beam carries a uniform serv: load w = 22 kN/m includes the weight of the beam. There is no later support other than that at the fixed end. Properties of W 10 x 77 258.83 P -- 2.10 w = 22 kN/m (K = 38.1 d = 269.24 h 1.5 m. (K = 38.1 ] 2.10 3 m. A = 14581 mm2 Lp = 2.799 m d = 269.24 mm L; = 13.811 m bị = 258.83 mm Lb = 3 m tf = 22.10 mm Fy 345 MPa %3D tw = 13.46 mm K = 38.10 mm Sx = 1408 x 103 mm3 E = 200,000 MPa Zx = 1599 x 103 mm³ a. Determine the value if the service load P due to the max. shear strength of the beam using LRFD. b. Determine the value if the service load P due to the max. shear strength of the beam using LRFD. c. Determine the value of the service load P due to the flexural strength of the beam using LRFD. d. Determine the value of the service load P due to the allowable
Problem 2 Design of Shear Members A cantilever beam has a span of 3 m. The beam carries a uniform serv: load w = 22 kN/m includes the weight of the beam. There is no later support other than that at the fixed end. Properties of W 10 x 77 258.83 P -- 2.10 w = 22 kN/m (K = 38.1 d = 269.24 h 1.5 m. (K = 38.1 ] 2.10 3 m. A = 14581 mm2 Lp = 2.799 m d = 269.24 mm L; = 13.811 m bị = 258.83 mm Lb = 3 m tf = 22.10 mm Fy 345 MPa %3D tw = 13.46 mm K = 38.10 mm Sx = 1408 x 103 mm3 E = 200,000 MPa Zx = 1599 x 103 mm³ a. Determine the value if the service load P due to the max. shear strength of the beam using LRFD. b. Determine the value if the service load P due to the max. shear strength of the beam using LRFD. c. Determine the value of the service load P due to the flexural strength of the beam using LRFD. d. Determine the value of the service load P due to the allowable
Elements Of Electromagnetics
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![Problem 2 Design of Shear Members
A cantilever beam has a span of 3 m. The beam carries a uniform service
load w = 22 kN/m includes the weight of the beam. There is no lateral
support other than that at the fixed end.
Properties of W 10 x 77
258.83
P
|2.10
w = 22 kN/m
(K = 38.1
d = 269.24
h
1.5 m.
(K = 38.1
3 m.
|22.10
A = 14581 mm²
Lp = 2.799 m
d = 269.24 mm
L; = 13.811 m
bị = 258.83 mm
Lb = 3 m
tị = 22.10 mm
Fy
345 MPa
%3D
tw = 13.46 mm
K = 38.10 mm
Sx = 1408 x 103 mm³
E = 200,000 MPa
Zx = 1599 x 103 mm³
a. Determine the value if the service load P due to the max. shear
strength of the beam using LRFD.
b. Determine the value if the service load P due to the max. shear
strength of the beam using LRFD.
c. Determine the value of the service load P due to the flexural
strength of the beam using LRFD.
d. Determine the value of the service load P due to the allowable
bending strength of the beam using ASD.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71a7f33a-13e3-42a8-bcae-0692518af53d%2Fa4d852f2-3541-4599-8512-609f89ea4ab6%2Fogr1iyb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 2 Design of Shear Members
A cantilever beam has a span of 3 m. The beam carries a uniform service
load w = 22 kN/m includes the weight of the beam. There is no lateral
support other than that at the fixed end.
Properties of W 10 x 77
258.83
P
|2.10
w = 22 kN/m
(K = 38.1
d = 269.24
h
1.5 m.
(K = 38.1
3 m.
|22.10
A = 14581 mm²
Lp = 2.799 m
d = 269.24 mm
L; = 13.811 m
bị = 258.83 mm
Lb = 3 m
tị = 22.10 mm
Fy
345 MPa
%3D
tw = 13.46 mm
K = 38.10 mm
Sx = 1408 x 103 mm³
E = 200,000 MPa
Zx = 1599 x 103 mm³
a. Determine the value if the service load P due to the max. shear
strength of the beam using LRFD.
b. Determine the value if the service load P due to the max. shear
strength of the beam using LRFD.
c. Determine the value of the service load P due to the flexural
strength of the beam using LRFD.
d. Determine the value of the service load P due to the allowable
bending strength of the beam using ASD.
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