PROBLEM 2: An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. (Ans: v = 1.95x10-3m/s) Detailed assumptions: The size of the cell is negligible compared to the length of the circuit. Copper resisitivity: p = 1.80×10-8N-m - Copper density: D = 8.96×10°kg-m-3 - Copper relative atomic mass: ma = 63.5 g/mol

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Chapter1: Units, Trigonometry. And Vectors
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PROBLEM 2:
An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its
negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the
drift velocity in the wire if there is one free electron per copper atom.
(Ans: v =
1.95x10-3m/s)
Detailed assumptions:
The size of the cell is negligible compared to the length of the circuit.
Copper resisitivity: p = 1.80×10-8N-m
- Copper density: D = 8.96×10°kg-m-3
- Copper relative atomic mass: ma = 63.5 g/mol
Transcribed Image Text:PROBLEM 2: An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. (Ans: v = 1.95x10-3m/s) Detailed assumptions: The size of the cell is negligible compared to the length of the circuit. Copper resisitivity: p = 1.80×10-8N-m - Copper density: D = 8.96×10°kg-m-3 - Copper relative atomic mass: ma = 63.5 g/mol
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