Problem #2 A W 300 x 97 kg/m beam has a simple span of 6 m. It carries a uniformly distributed dead load including its own weight of 15 kN/m. The beam has full lateral bracing. Use LRFD analysis Prop. of W 300 mm x 97 d = 307.85 mm bf = 304.80 mm t = 15.37 mm tw = 9.91 mm. U = 1.2 DL + 1.6 LL Sx = 1440 x 103 mm3 Zx = 1586 x 103 mm³ Fy = 345 MPa E = 200000 MPa. %3D %3D O Determine the safe service live load that the beam could support based on its flexural capacity. ø = 0.90 O Determine the safe service live load that the beam could support based on its shear capacity. ø = 0.90 ® Determine the safe live concentrated load at its midspan that the beam could support based on its live load allowable deflection of 1/360 of span. Flexural rigidity El = 44000 KN.m²
Problem #2 A W 300 x 97 kg/m beam has a simple span of 6 m. It carries a uniformly distributed dead load including its own weight of 15 kN/m. The beam has full lateral bracing. Use LRFD analysis Prop. of W 300 mm x 97 d = 307.85 mm bf = 304.80 mm t = 15.37 mm tw = 9.91 mm. U = 1.2 DL + 1.6 LL Sx = 1440 x 103 mm3 Zx = 1586 x 103 mm³ Fy = 345 MPa E = 200000 MPa. %3D %3D O Determine the safe service live load that the beam could support based on its flexural capacity. ø = 0.90 O Determine the safe service live load that the beam could support based on its shear capacity. ø = 0.90 ® Determine the safe live concentrated load at its midspan that the beam could support based on its live load allowable deflection of 1/360 of span. Flexural rigidity El = 44000 KN.m²
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Problem #2
A W 300 x 97 kg/m beam has a simple span of
6 m. It carries a uniformly distributed dead
load including its own weight of 15 kN/m. The
beam has full lateral bracing. Use LRFD
analysis
Prop. of W 300 mm x 97
d = 307.85 mm
bf = 304.80 mm
t = 15.37 mm
tw = 9.91 mm.
U = 1.2 DL + 1.6 LL
Sx = 1440 x 103 mm3
Zx = 1586 x 103 mm³
Fy = 345 MPa
E = 200000 MPa.
%3D
%3D
%3D
O Determine the safe service live load
that the beam could support based on
its flexural capacity. ø = 0.90
2 Determine the safe service live load
that the beam could support based on
its shear capacity. ø = 0.90
® Determine the safe live concentrated
load at its midspan that the beam could
support based on its live load allowable
deflection of 1/360 of span. Flexural
rigidity El = 44000 KN.m²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8860f4b2-59c0-4aba-bccc-5f77bb9fd06e%2F66281b09-e2c5-4ede-a897-a4215752542d%2Fb93fh7a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem #2
A W 300 x 97 kg/m beam has a simple span of
6 m. It carries a uniformly distributed dead
load including its own weight of 15 kN/m. The
beam has full lateral bracing. Use LRFD
analysis
Prop. of W 300 mm x 97
d = 307.85 mm
bf = 304.80 mm
t = 15.37 mm
tw = 9.91 mm.
U = 1.2 DL + 1.6 LL
Sx = 1440 x 103 mm3
Zx = 1586 x 103 mm³
Fy = 345 MPa
E = 200000 MPa.
%3D
%3D
%3D
O Determine the safe service live load
that the beam could support based on
its flexural capacity. ø = 0.90
2 Determine the safe service live load
that the beam could support based on
its shear capacity. ø = 0.90
® Determine the safe live concentrated
load at its midspan that the beam could
support based on its live load allowable
deflection of 1/360 of span. Flexural
rigidity El = 44000 KN.m²
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