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Problem 2: A uniform beam of length L and mass M has its lower end pivoted at Pon the floor, making an angle 0 with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass Mis suspended from a rope that is attached to the beam one-fourth L from its upper end. M

Problem 2: A uniform beam of length L and mass M has its lower end pivoted at Pon the floor, making an angle 0 with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass Mis suspended from a rope that is attached to the beam one-fourth L from its upper end. M

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Problem 2: A uniform beam of length L and mass M has its lower end pivoted at P on the floor, making an angle 0 with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass M is suspended from a rope that is attached to the beam one-fourth L from its upper end. y M M. P Part (a) Write an expression for the y-component P, of the force exerted by the pivot on the beam. Expression : Py =. Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(o), cos(0), cotan(0), sin(a), sin(o), sin(0), tan(0), , 0, c, d, g, M, T Part (b) Write an expression for the tension T in the horizontal cable AB Expression : T = Select from the variables below to write your expression. Note that all variables may not be required. cocotan(0), cos(a), cos(4), cos(0), cotan(0), sin(a), sin(), sin(0), tan(0), a, c, d, g, M, q Part (c) Write an expression for the x-component P, of the force exerted by the pivot on the beam, in terms of T. Expression : Px = %3D Select from the variables below to write your expression. Note that all variables may not be required. cos(0), cotan(0), sin(8), tan(0), a, ß, 0, d, h, j, k, P, q, T, z Part (d) What is the tension in the horizontal cable, in newtons, if the mass of the beam is 27 kg, the length of the beam is 6 m, and the angle is 22°? Numeric : A numeric value is expected and not an expression. T =
Transcribed Image Text:Problem 2: A uniform beam of length L and mass M has its lower end pivoted at P on the floor, making an angle 0 with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass M is suspended from a rope that is attached to the beam one-fourth L from its upper end. y M M. P Part (a) Write an expression for the y-component P, of the force exerted by the pivot on the beam. Expression : Py =. Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(o), cos(0), cotan(0), sin(a), sin(o), sin(0), tan(0), , 0, c, d, g, M, T Part (b) Write an expression for the tension T in the horizontal cable AB Expression : T = Select from the variables below to write your expression. Note that all variables may not be required. cocotan(0), cos(a), cos(4), cos(0), cotan(0), sin(a), sin(), sin(0), tan(0), a, c, d, g, M, q Part (c) Write an expression for the x-component P, of the force exerted by the pivot on the beam, in terms of T. Expression : Px = %3D Select from the variables below to write your expression. Note that all variables may not be required. cos(0), cotan(0), sin(8), tan(0), a, ß, 0, d, h, j, k, P, q, T, z Part (d) What is the tension in the horizontal cable, in newtons, if the mass of the beam is 27 kg, the length of the beam is 6 m, and the angle is 22°? Numeric : A numeric value is expected and not an expression. T =
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