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Problem 2 ( ) A microscopic spring-mass system has a mass m = 5 x 10-26 kg and the energy gap between the 2nd and 3rd excited states is 7 eV. a) .) Calculate in joules, the energy gap the 1st and 2nd excited states: E= bet J b) (. What is the energy gap between the 4th and 7th excited states: E= Jev c) () To find the energy of the ground state, Whquation can be used? (check the formula_sheet and select the number of the equation)

Problem 2 ( ) A microscopic spring-mass system has a mass m = 5 x 10-26 kg and the energy gap between the 2nd and 3rd excited states is 7 eV. a) .) Calculate in joules, the energy gap the 1st and 2nd excited states: E= bet J b) (. What is the energy gap between the 4th and 7th excited states: E= Jev c) () To find the energy of the ground state, Whquation can be used? (check the formula_sheet and select the number of the equation)

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Problem 2 ( ) A microscopic spring-mass system has a mass m = 5 x 10-26 kg and the energy gap between the 2nd and 3rd excited states is 7 eV. >) Calculate in joules, the energy gap the 1st and 2nd excited states: E= bet b) (= What is the energy gap between the 4th and 7th excited states: E= ev c) (- -) To find the energy of the ground state, Wluation can be used ? (check the formula_sheet and select the number of the equation) d) (t) Which of the following substitutions can be used to calculate the energy of the ground state? 01/27 02 x 7 -) The energy of the ground state is: E= eV f) To find the stiffness of the spring, which equation can be used ? (check the formula_sheet and select the number of the equation) Which of the following substitutions can be used to calculate the stiffness of the spring? 6.582x10-16 5x10-26 O(5 x 10-26) 7 6.582x10-16 O(5 x 10-26) (6.582x10-16 7 6.582x30-16 5x10-26 O(5 x 10-26) (7)² O(5 x 10-26) (6.582 x 10-16) ² 02- 7 (6.582x10-16) 2 h). ) The stiffness of the spring is: K = (N/m) ..) What is the smallest amount of vibrational energy that can be added to this system? E = eV (6.582x10-16)2 2 (6.582 × 10-16) (7) (6.582 x 10-¹6) (7)
Transcribed Image Text:Problem 2 ( ) A microscopic spring-mass system has a mass m = 5 x 10-26 kg and the energy gap between the 2nd and 3rd excited states is 7 eV. >) Calculate in joules, the energy gap the 1st and 2nd excited states: E= bet b) (= What is the energy gap between the 4th and 7th excited states: E= ev c) (- -) To find the energy of the ground state, Wluation can be used ? (check the formula_sheet and select the number of the equation) d) (t) Which of the following substitutions can be used to calculate the energy of the ground state? 01/27 02 x 7 -) The energy of the ground state is: E= eV f) To find the stiffness of the spring, which equation can be used ? (check the formula_sheet and select the number of the equation) Which of the following substitutions can be used to calculate the stiffness of the spring? 6.582x10-16 5x10-26 O(5 x 10-26) 7 6.582x10-16 O(5 x 10-26) (6.582x10-16 7 6.582x30-16 5x10-26 O(5 x 10-26) (7)² O(5 x 10-26) (6.582 x 10-16) ² 02- 7 (6.582x10-16) 2 h). ) The stiffness of the spring is: K = (N/m) ..) What is the smallest amount of vibrational energy that can be added to this system? E = eV (6.582x10-16)2 2 (6.582 × 10-16) (7) (6.582 x 10-¹6) (7)
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