Problem 2: A composite shaft is composed of a solid section AB and a tubular section BC, both of which have circular cross sections. Section AB is made of steel and has a radius of 1 in. Section BC consists of a brass core, with a radius of 0.5 in, surrounded by a steel tube, with an inner radius of 0.5 in and an outer radius of 1 in. Use Gs = 11,500 ksi for steel and Gb = 5600 ksi for brass. The shaft is attached to a fixed support at A, and a torque of T = 50 ft-lb is applied at the free end C. 0.5 in 1 in 2 ft B T = 50 ft-lb 3 ft (a) Calculate the total angle of twist (magnitude only) between A and C. (b) Calculate the maximum shear stress in the brass. (c) Calculate the maximum shear stress in the steel.

Materials Science And Engineering Properties
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Chapter14: Material Selection
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Problem 2: A composite shaft is composed of a solid section AB and a tubular section BC, both
of which have circular cross sections. Section AB is made of steel and has a radius of 1 in.
Section BC consists of a brass core, with a radius of 0.5 in, surrounded by a steel tube, with an
inner radius of 0.5 in and an outer radius of 1 in. Use Gs = 11,500 ksi for steel and Gb = 5600 ksi
for brass. The shaft is attached to a fixed support at A, and a torque of T = 50 ft-lb is applied at
the free end C.
0.5 in
1 in
2 ft
B
T = 50 ft-lb
3 ft
(a) Calculate the total angle of twist
(magnitude only) between and C.
(b) Calculate the maximum shear stress in the
brass.
(c) Calculate the maximum shear stress in the
steel.
Transcribed Image Text:Problem 2: A composite shaft is composed of a solid section AB and a tubular section BC, both of which have circular cross sections. Section AB is made of steel and has a radius of 1 in. Section BC consists of a brass core, with a radius of 0.5 in, surrounded by a steel tube, with an inner radius of 0.5 in and an outer radius of 1 in. Use Gs = 11,500 ksi for steel and Gb = 5600 ksi for brass. The shaft is attached to a fixed support at A, and a torque of T = 50 ft-lb is applied at the free end C. 0.5 in 1 in 2 ft B T = 50 ft-lb 3 ft (a) Calculate the total angle of twist (magnitude only) between and C. (b) Calculate the maximum shear stress in the brass. (c) Calculate the maximum shear stress in the steel.
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